在python的燒瓶休息api中的錯誤404

Question

我是新來的燒瓶Restful api我想讓休息api得到JSON data.While輸入curl命令我得到404錯誤。這裏是代碼任何人都可以請幫助。

#flask/bin/python 
from flask import Flask, jsonify, abort, request, make_response,url_for,render_template 
from flask.ext.restful import Api, Resource 
#from flask.ext.restful import restful, Api 
app = Flask(__name__, static_folder ="\Flae\app\default") 
api= Api(app) 

@app.errorhandler(404) 
def page_not_found(e): 
return 'Sorry, Nothing at this URL.', 404 


class Task(Resource): 

    tasks = [ 
     { 
      'id': 1, 
      'message': u'You are notified' 
     }, 
     { 
      'id': 2, 
      'message': u'You are notified' 
     } 
    ] 

    def get_tasks(): 
     return jsonify({ 'tasks': tasks }) 

api.add_resource(Task, '/api/v1/tasks') 

if __name__ == '__main__': 
    app.run() 

顯示的錯誤是：

C:\Users\Chaitanya>curl http://127.0.0.1:5000/ 
    Sorry, Nothing at this URL. 
    C:\Users\Chaitanya>curl http://127.0.0.1:5000/api/v1/tasks 
    {"status": 500, "message": "Internal Server Error"} 
    C:\Users\Chaitanya> 

日誌中生成是：

C:\Users\Chaitanya\Desktop\Flae\batch-fuogy-01\default>python main.py 
    * Running on http://127.0.0.1:5000/ 
    * Restarting with reloader 
    127.0.0.1 - - [10/Feb/2015 17:39:09] "GET /api/v1/tasks HTTP/1.1" 500 - 
    Traceback (most recent call last): 
    File "D:\Python27\lib\site-packages\flask\app.py", line 1836, in __call__ 
    return self.wsgi_app(environ, start_response) 
    File "D:\Python27\lib\site-packages\flask\app.py", line 1820, in wsgi_app 
    response = self.make_response(self.handle_exception(e)) 
    File "D:\Python27\lib\site-packages\flask_restful\__init__.py", line 263,in error_router 
    return original_handler(e) 
    File "D:\Python27\lib\site-packages\flask\app.py", line 1403, in handle_exception 
    reraise(exc_type, exc_value, tb) 
    File "D:\Python27\lib\site-packages\flask_restful\__init__.py", line 260,in error_router 
    return self.handle_error(e) 
    File "D:\Python27\lib\site-packages\flask\app.py", line 1817, in wsgi_app 
    response = self.full_dispatch_request() 
    File "D:\Python27\lib\site-packages\flask\app.py", line 1477, in full_dispatch_request 
    rv = self.handle_user_exception(e) 
    File "D:\Python27\lib\site-packages\flask_restful\__init__.py", line 263, in error_router 
    return original_handler(e) 
    File "D:\Python27\lib\site-packages\flask\app.py", line 1381, in handle_user_exception 
    reraise(exc_type, exc_value, tb) 
    File "D:\Python27\lib\site-packages\flask_restful\__init__.py", line 260, in error_router 
return self.handle_error(e) 
    File "D:\Python27\lib\site-packages\flask\app.py", line 1475, in full_dispatch_request 
    rv = self.dispatch_request() 
    File "D:\Python27\lib\site-packages\flask\app.py", line 1461, in dispatch_request 
    return self.view_functions[rule.endpoint](**req.view_args) 
    File "D:\Python27\lib\site-packages\flask_restful\__init__.py", line 431, in wrapper 
    resp = resource(*args, **kwargs) 
    File "D:\Python27\lib\site-packages\flask\views.py", line 84, in view 
    return self.dispatch_request(*args, **kwargs) 
    File "D:\Python27\lib\site-packages\flask_restful\__init__.py", line 516, in dispatch_request 
    assert meth is not None, 'Unimplemented method %r' % request.method 
    AssertionError: Unimplemented method 'GET' 

Answer 1

，因爲它要求的瓶，寧靜的文檔，您應該重命名 'get_tasks' 方法 '得到'：

https://flask-restful.readthedocs.org/en/0.3.1/quickstart.html#a-minimal-api。