的Android - org.ksoap2.soapfault無法施展

Question

我想從Android客戶端訪問Java Web服務，但它顯示了我的錯誤：

「java.lang.classcastexception org.ksoap2.soapfault無法投射到org.ksoap2.serialization.soapobject「

你能幫助我嗎？

這裏是我的客戶端web服務代碼：

import java.lang.reflect.Method; 

import android.app.Activity; 
import android.os.Bundle; 
import android.content.Context; 
import android.content.Intent; 
import android.view.Menu; 
import android.view.MenuItem; 
import android.view.View; 
import android.view.Window; 
import android.widget.EditText; 

import android.widget.TextView; 
import org.ksoap2.SoapEnvelope; 
import org.ksoap2.serialization.SoapObject; 
import org.ksoap2.serialization.SoapSerializationEnvelope; 
import org.ksoap2.transport.AndroidHttpTransport; 
import org.ksoap2.transport.HttpTransportSE; 

public class Loginuser extends Activity{ 


public static final int MENU1 = Menu.FIRST; 
public static final int MENU2 = Menu.FIRST + 1; 
public static final int MENU3 = Menu.FIRST + 2; 
public static Context group; 

    private static final String SOAP_ACTION = ""; 
    private static final String METHOD_NAME = "logar"; 
    private static final String NAMESPACE = "http://wsproj.mycompany.com/"; 
    private static final String URL = "http://localhost:8084/wsproj/HelloWorld"; 


    EditText ura,pw; 

@Override 
public void onCreate(Bundle savedInstanceState) { 
    super.onCreate(savedInstanceState); 
    requestWindowFeature(Window.FEATURE_NO_TITLE); 
    setContentView(R.layout.loginuser); 

    } 


    public void logar(View X) { 
    CarregaTelaBolarq(); 
    } 

public void CarregaTelaBolarq(){ 

    ura=(EditText)findViewById(R.id.editText2); 
    String raforn = ura.getText().toString(); 

    SoapObject request = new SoapObject(NAMESPACE, METHOD_NAME); 


    request.addProperty("raforn",ura.getText().toString()); 

    SoapSerializationEnvelope envelope = new SoapSerializationEnvelope(SoapEnvelope.VER11); 

    envelope.setOutputSoapObject(request); 


try{ 

    HttpTransportSE androidHttpTransport = new HttpTransportSE(URL); 

    androidHttpTransport.call(SOAP_ACTION, envelope); 

    SoapObject sp = (SoapObject)envelope.bodyIn; 

    String result=sp.toString(); 

    if(result.equals("1")) 

      { 

       TextView tv; 
       tv=(TextView) findViewById(R.id.editText1); 
       tv.setText("foi: "); 
      } 
      else 
      { 
       TextView tv; 
       tv=(TextView) findViewById(R.id.editText1); 
       tv.setText("Msg from service: "); 
      }  

     } 
     catch(Exception e) 
     { 

      TextView tv=(TextView) findViewById(R.id.editText1); 
      tv.setText("ERROR: " + e.toString()); 
     } 

} 




public boolean onCreateOptionsMenu(Menu options) { 
options.add(0, MENU1, 0, "Página Principal"); 
options.add(0, MENU2, 0, "Manual"); 
options.add(0, MENU3, 0, "Sobre"); 

return super.onCreateOptionsMenu(options); } 


public boolean onOptionsItemSelected(MenuItem item) { 
    switch (item.getItemId()) { 
    case MENU1: 
     Intent mudarHome= new Intent(this, MainActivity.class); 
     startActivity(mudarHome); 
     return true; 

    case MENU2: 
     Intent mudarManual = new Intent(this, Manual.class); 
     startActivity(mudarManual); 
     return true; 

    case MENU3: 
     Intent mudarSobre = new Intent(this, Sobre.class); 
     startActivity(mudarSobre); 
     return true; 

     } 
     return false; 
     } 
    } 

Answer 1

這意味着沒有通過這些參數發現服務嘗試這個代碼，找出錯誤消息：

SoapFault error = (SoapFault)envelope.bodyIn; 
System.out.println("Error message : "+error.toString()); 

在我看來，你必須

用包名包含服務的類填寫SOAP_ACTION參數：

private static final String SOAP_ACTION = "http://com.mycompany.wsproj/HelloWorld"; 

和的.wsdl或WSDL（都去嘗試一下XD）

private static final String URL = "http://localhost:8084/wsproj/HelloWorld?wsdl"; 

最後一個重要的事情是結束Web服務的URL（當您使用的Android API）由IP改變本地主機：

private static final String URL = "http://10.0.2.2:8084/wsproj/HelloWorld?wsdl"; 

希望能幫到你！ ... 祝你好運 ！

Answer 2

當您處理SOAP Web服務時，可能會出現此問題一段時間。來自該服務的響應可以是SOAP對象，如果出現錯誤，如錯誤憑據傳遞，則Response將帶有錯誤消息，並且它是SOAPFAULT對象。因此，更新您的解析代碼以檢查響應對象的類型。

這種代碼可以解決你的問題，

if (envelope.bodyIn instanceof SoapFault) { 
    String str= ((SoapFault) envelope.bodyIn).faultstring; 
    Log.i("", str); 

    // Another way to travers through the SoapFault object 
/* Node detailsString =str= ((SoapFault) envelope.bodyIn).detail; 
    Element detailElem = (Element) details.getElement(0) 
       .getChild(0); 
    Element e = (Element) detailElem.getChild(2);faultstring; 
    Log.i("", e.getName() + " " + e.getText(0)str); */ 
} else { 
    SoapObject resultsRequestSOAP = (SoapObject) envelope.bodyIn; 
    Log.d("WS", String.valueOf(resultsRequestSOAP)); 
}