2017-02-01 69 views
0

我使用的是Java8,Hibernate 5.2.1.Final,JPA2,Spring 4.3.1.RELEASE和MySQL。休眠:鍵'重複'的重複條目'173-604'

我有一種情況,我在一行上做了select,但得到了ConstraintViolationException

首先,我有下表。如果我做了選擇通過MySQL工作臺,它有一行數據:

SELECT * FROM www.person; 

結果

ID,    UID,     JOINING_DATE, LASTACCESS_DATE, DISPLAY_NAME, EMAIL_ADDRESS, AVATAR, PROVIDER 
'176', 'PHblCtu5odMNQEaOu9TOmGgpsJM2', '1485981515384', '1485981525475', 'One',  '[email protected]', null,  '1' 

然後,我的代碼有以下幾點:

的Java

@Override 
public Person findByUid(String uid, Integer provider) { 
    StringBuilder sb = new StringBuilder(); 
    sb.append(" select e.* "); 
    sb.append(" from "); 
    sb.append(" www.person as e "); 
    sb.append(" where e.uid = :uid "); 
    sb.append(" and e.provider = :provider "); 
    Query q = entityManager.createNativeQuery(sb.toString(), Person.class); 
    q.setParameter("uid", uid); 
    q.setParameter("provider", provider); 
    Person person = (Person) q.getResultList().stream().findFirst().orElse(new Person()); 
    return person; 
} 

其他e uid(PHblCtu5odMNQEaOu9TOmGgpsJM2)和提供者(1)匹配上面的行。

但上述q.getResultList()被調用時,我得到:

錯誤

22:28:25,843 WARN [org.hibernate.engine.jdbc.spi.SqlExceptionHelper] (default task-14) SQL Error: 1062, SQLState: 23000 
22:28:25,844 ERROR [org.hibernate.engine.jdbc.spi.SqlExceptionHelper] (default task-14) Duplicate entry '173-604' for key 'PRIMARY' 
22:28:25,845 INFO [org.hibernate.engine.jdbc.batch.internal.AbstractBatchImpl] (default task-14) HHH000010: On release of batch it still contained JDBC statements 
org.hibernate.exception.ConstraintViolationException: could not execute statement 

@Entity 
@Table(name = "person") 
@XmlRootElement(name = "person") 
public class Person extends AbstractDomain<Long> { 

    // private static final Logger logger = Logger.getLogger(
    // ClassName.class.getName()); 

    @Id 
    @GeneratedValue(strategy = GenerationType.IDENTITY) 
    private Long id; 

    @Size(min = 1, max = 45) 
    @Column(name = "UID") 
    private String uid; 

    @Column(name = "JOINING_DATE", nullable = false) 
    private Long joiningDate; 

    @Column(name = "LASTACCESS_DATE", nullable = false) 
    private Long lastAccessDate; 

    @Size(min = 1, max = 85) 
    @Column(name = "DISPLAY_NAME", nullable = false) 
    private String displayName; 

    @Size(min = 5, max = 55) 
    @Column(name = "EMAIL_ADDRESS", nullable = false, unique = true) 
    private String emailAddress; 

    @ManyToMany(cascade = CascadeType.ALL, fetch = FetchType.EAGER) 
    @JoinTable(name = "person_language", joinColumns = { 
      @JoinColumn(name = "PER_ID", referencedColumnName = "ID") }, inverseJoinColumns = { 
        @JoinColumn(name = "LANG_ID", referencedColumnName = "LANGUAGE_CODE", unique = true) }) 
    private Set<Language> languages; 

    @OneToMany(cascade = CascadeType.ALL, fetch = FetchType.EAGER, orphanRemoval = true) 
    @JoinTable(name = "person_location", joinColumns = { 
      @JoinColumn(name = "PER_ID", referencedColumnName = "ID") }, inverseJoinColumns = { 
        @JoinColumn(name = "LOC_ID", referencedColumnName = "ID", unique = true) }) 
    private Set<LocationPerson> locations = null; 

    @OneToMany(cascade = CascadeType.ALL, fetch = FetchType.EAGER) 
    @JoinTable(name = "person_job_favourites", joinColumns = { 
      @JoinColumn(name = "PER_ID", referencedColumnName = "ID") }, inverseJoinColumns = { 
        @JoinColumn(name = "JOB_ID", referencedColumnName = "ID", unique = true) }) 
    private Set<Job> favouriteJobs; 

問題

我不知道你可以從執行select查詢得到ConstraintViolationException。如果任何人可以建議我如何解決這個問題,我將不勝感激。

p.s.我可以在上面的Bean上成功執行merge

+0

你執行該交易的任何操作? –

+0

另外,可以添加與該特定人員ID相對應的表person_language,person_location,person_job_favorites的行 –

+0

是的,我在'select'之前的同一個事務中執行同一對象('person')的'合併'。該代碼不會在'merge'錯誤,而是在'select'錯誤。 – Richard

回答

0

找到了解決辦法:

我需要設置每個在合併方法聯接的列的:

  person.setLanguages(foundPerson.getLanguages()); 
      person.setLocations(foundPerson.getLocations()); 
      person.setFavoriuteJobs(foundPerson.getFavoriuteJobs());