異常處理的冒險III - 更新

Question

我有這樣的Java代碼骨架 -

 try { 
      Question q = null; //List of questions. I have put 3 in the list, in my main function 
      int i = 0; 
      while (i <= questions.size()) { 
       System.out.println("iteration " + i); 
       q = questions.get(i); 
       try { 
        try { 
         System.out.println("Script completed"); 
         break; 
        } catch (Exception e) { 
         // script is still executing... continue 
        } 
        //My entire logic is here.An exception is thrown in the first iteration 
        i++; 
       } catch (Exception e) { 
        //The thrown exception is caught here 
        try { 
        //The caught exception is handled here 
       } catch (IOException ioe) { 
        System.out.println("IO Exception.."); 
       } 
      } 
     } 
     } catch (IOException ioe) { 
      System.out.println("No more communication due to the lack of data"); 
     } catch (IllegalMonitorStateException imse) { 
      System.out.println("Illegal Monitor State Exception"); 
     } catch (IllegalThreadStateException itse) { 
      System.out.println("Illegal Thread State Exception"); 
     } 

---

而且輸出我得到的是有點像這樣 -

iteration 0 
//Exception handling related output 

iteration 0 //repeated because i++ doesn't happen since exception is thrown 
//Execution takes place normally 

iteration 1 
//???????? - Here is where i am facing the problem. I am not getting 

輸出完全。我知道爲什麼我仍然在第1次迭代（這與i ++有關，因爲第一次拋出異常而不會發生一次）。但任何人都可以幫助我如何成功執行此迭代呢？

Answer 1

您需要檢查哪個catch塊在每次迭代中被執行。如果在//try3或//try4（或者根本沒有異常拋出）中引發異常，則執行i++將執行。

如果異常在//try2（無論是前//try3或後//catch4）拋出，然後i++不會執行。