要使用實施登錄/註冊系統REST API MySql你需要一個服務器端的API，例如在PHP中操縱數據庫。
你需要的東西一樣，在服務器端：
// check for tag type
if ($tag == 'login') {
// Request type is check Login
$email = $_POST['email'];
$password = $_POST['password'];
// check for user
$user = $db->getUserByEmailAndPassword($email, $password);
if ($user != false) {
// user found
$response["error"] = FALSE;
$response["uid"] = $user["unique_id"];
$response["user"]["name"] = $user["name"];
$response["user"]["email"] = $user["email"];
$response["user"]["created_at"] = $user["created_at"];
$response["user"]["updated_at"] = $user["updated_at"];
echo json_encode($response);
} else {
// user not found
// echo json with error = 1
$response["error"] = TRUE;
$response["error_msg"] = "Incorrect email or password!";
echo json_encode($response);
}
和查詢數據庫的功能：
public function getUserByEmailAndPassword($username, $password) {
$query = $this->dbh->prepare("SELECT * FROM users2 WHERE username = :username");
$query->bindParam(':username', $username);
$result = $query->execute();
// check for results
if ($query->rowCount() > 0) {
$result = $query->fetch(PDO::FETCH_ASSOC);
$salt = $result['salt'];
$encrypted_password = $result['encrypted_password'];
$hash = $this->checkhashSSHA($salt, $password);
// check for password equality
if ($encrypted_password == $hash) {
// user authentication details are correct
return $result;
}
} else {
// user not found
return false;
}
}
Android的 '呼籲' 的PHP腳本：
private static String login_tag = "login";
public void loginUser(String username, String password) throws ExecutionException, InterruptedException {
// Building Parameters
List<NameValuePair> params = new ArrayList<NameValuePair>();
params.add(new BasicNameValuePair("tag", login_tag));
params.add(new BasicNameValuePair("username", username));
params.add(new BasicNameValuePair("password", password));
jsonParser = new DbHandler(activity, this, params).execute();
}
這裏是DbHandler：
public DbHandler1(Activity activity, MyCallback dbIntf, List<NameValuePair> params) {
this.activity = activity;
intf = dbIntf;
this.params = params;
}
public JSONObject makeHttpRequest() {
// Making HTTP request
try {
DefaultHttpClient httpClient = new DefaultHttpClient();
HttpPost httpPost = new HttpPost(MainActivity.baseUrl);
//If database contains greek characters instantiate with UTF-8 Encoding
httpPost.setEntity(new UrlEncodedFormEntity(params, "UTF-8"));
HttpResponse httpResponse = httpClient.execute(httpPost);
HttpEntity httpEntity = httpResponse.getEntity();
is = httpEntity.getContent();
} catch (HttpHostConnectException e) {
new Handler(Looper.getMainLooper()).post(new Runnable() {
@Override
public void run() {
Toast.makeText(activity, R.string.connection_error, Toast.LENGTH_LONG).show();
}
});
} catch (IOException e) {
e.printStackTrace();
}
try {
//If database contains greek characters instantiate with UTF-8 Encoding
BufferedReader reader = new BufferedReader(new InputStreamReader(
is, "UTF-8"), 8);
StringBuilder sb = new StringBuilder();
String line = null;
while ((line = reader.readLine()) != null) {
sb.append(line + "\n");
}
is.close();
json = sb.toString();
} catch (Exception e) {
Log.e("Buffer Error", "Error converting result " + e.toString());
}
try {
jObj = new JSONObject(json);
} catch (JSONException e) {
Log.e("JSON Parser", "Error parsing data " + e.toString());
}
// return JSON String
return jObj;
}
@Override
protected JSONObject doInBackground(Void... params) {
jObj = makeHttpRequest();
return jObj;
}
@Override
protected void onPostExecute(JSONObject jsonObject) {
super.onPostExecute(jsonObject);
try {
intf.onRemoteCallComplete(jsonObject);
} catch (JSONException e) {
e.printStackTrace();
} catch (ExecutionException e) {
e.printStackTrace();
} catch (InterruptedException e) {
e.printStackTrace();
}
}
因此，PHP腳本'捕捉'標籤，如果用戶存在，它會返回一個JSON響應給設備。例如：
{
"tag": "login",
"success": 1,
"error": 0,
}
從MySql服務器傳輸的數據必須是JSON編碼的。
在Android設備上，您必須閱讀JSON響應並採取相應措施。
請看這裏瞭解更多詳情。
很大。這更像它。 – 2015-03-02 18:27:43