如何連接元組中的字符串？

Question

input:[("xyz",100),("tao",90),("quinee",100)] 

當數字相等時字符串將被連接成一個列表。

output:[(["xyz","quinee"],100),(["tao"],90)] 

Answer 1

itertools.groupby可以做到這一點。

from itertools import groupby 

def key(x): return x[1] 

input=[("xyz",100),("tao",90),("quinee",100)] 

output = [ 
    (list(string for string,index in group),index) 
    for index,group in groupby(sorted(input, key=key, reverse=True), key=key)] 

assert output == [(["xyz","quinee"],100),(["tao"],90)] 

Answer 2

您可以使用defaultdict：

from collections import defaultdict 

l = [("xyz",100),("tao",90),("quinee",100)] 

d = defaultdict(list) 
for i in l: 
    d[i[1]].append(i[0]) 

r = [(j, i) for i, j in d.items()] 
print(r) 
# [(['tao'], 90), (['xyz', 'quinee'], 100)] 

Answer 3

嘗試使用defaultdict，，默認其值列表：

from collections import defaultdict 

def concat(lst): 
    d = defaultdict(list) 
    for k, v in lst: 
     d[v].append(k) 
    return [(v, k) for k, v in d.items()]