我遇到了一些使用getElementById的JavaScript問題。它可以在FF,Safari和Chrome中正常工作,但IE(8 - 沒有嘗試過其他)可以保留。Internet Explorer在getElementById上拋出錯誤
HTML的相關位是一個div叫topnav:
<div id="topnav">
... some HTML ...
<div>
<div id="sub_1" class="lowernav">
... some HTML ...
</div>
<div id="sub_2" class="lowernav">
... some HTML ...
</div>
在我的JavaScript,我想找到topnav。完整的代碼(最多的地方撈出)是這樣的:
<script>
window.onload = init();
function init() {
// Show current menu
showCurrentMenu();
}
function showCurrentMenu() {
hideMenus(); // Hide all menus and then show the current one
topnav = document.getElementById('topnav');
... rest of code ...
}
function hideMenus() {
var divlist = document.getElementsByTagName('div');
for(var ii=0; ii<divlist.length; ii++) {
if(divlist[ii].className != divlist[ii].className.replace('lowernav','')) {
divlist[ii].className += ' hidden';
}
}
}
...然後一些其他的代碼還沒有達到...
難道我做錯了什麼嗎?這可能是一件非常明顯的事情,但對我而言,我看不到它!所有的建議非常感謝。
ETA:好吧,這裏是整個代碼,因爲它目前爲:
<script>
window.onload = init;
function init() {
// Show current menu
showCurrentMenu;
// Attach 'onmouseover' event to main menu items
topnav = document.getElementById('topnav');
// Get all items in list
var menulist = topnav.getElementsByTagName('a');
for(var ii=0; ii<menulist.length; ii++) {
menulist[ii].onmouseover = showMenu;
}
document.getElementById('mainHomeNav').onmouseout = restoreMenu;
}
function restoreMenu(e) {
var targ;
if (!e) var e = window.event;
if (e.target) targ = e.target;
else if (e.srcElement) targ = e.srcElement;
if (targ.nodeType == 3) // defeat Safari bug
targ = targ.parentNode;
if (targ.id == "mainHomeNav") {
showCurrentMenu;
}
}
function hideMenus() {
var divlist = document.getElementsByTagName('div');
for(var ii=0; ii<divlist.length; ii++) {
if(divlist[ii].className != divlist[ii].className.replace('lowernav','')) {
divlist[ii].className += ' hidden';
}
}
}
function showCurrentMenu() {
hideMenus;
topnav = document.getElementById('topnav');
// Get all items in list
var menulist = topnav.getElementsByTagName('a');
for(var ii=0; ii<menulist.length; ii++) {
if(menulist[ii].className != menulist[ii].className.replace('thisSection','')) {
var thisid = menulist[ii].id;
var thissubmenu = document.getElementById(thisid + '_sub');
thissubmenu.className = thissubmenu.className.replace(/hidden/g,'');
}
}
}
function showMenu() {
hideMenus;
// show this menu
var submenu_id = this.id + '_sub';
var submenu = document.getElementById(submenu_id);
submenu.className = submenu.className.replace(/hidden/g,'');
}
</script>
+1爲正確的答案。在嘗試調試時容易犯錯誤,容易錯過。 – Spudley 2011-01-14 15:47:10