將curl示例轉換爲pycurl

有人可以將以下PostMark curl示例轉換爲pycurl嗎？將curl示例轉換爲pycurl

curl -X POST "http://api.postmarkapp.com/email" \ 

-H "Accept: application/json" \ 

-H "Content-Type: application/json" \ 

-H "X-Postmark-Server-Token: ed742D75-5a45-49b6-a0a1-5b9ec3dc9e5d" \ 

-v \ 

-d "{From: '[email protected]', To: '[email protected]', Subject: 'Postmark test', HtmlBody: '<html><body><strong>Hello</strong> dear Postmark user.</body></html>'}"

來源

2014-04-02 Darth

我可以，但我不會。顯示你的代碼，我會修改。對我來說更容易。 –

你可以使用這樣的東西。這是一個基本的實現，但它應該工作。

import pycurl, json 

github_url = 'https://api.postmarkapp.com/email' 

data = json.dumps({"From": "[email protected]", "To": "[email protected]", "Subject": "Pycurl", "TextBody": "Some text"}) 

c = pycurl.Curl() 
c.setopt(pycurl.URL, github_url) 
c.setopt(pycurl.HTTPHEADER, ['X-Postmark-Server-Token: API_TOKEN_HERE','Accept: application/json']) 
c.setopt(pycurl.POST, 1) 
c.setopt(pycurl.POSTFIELDS, data) 
c.perform()

來源

2014-04-02 14:07:06

非常簡潔的例子。幫了我很多:) – dhruvvyas90

將curl示例轉換爲pycurl

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