替換Apache POI中的表列值

Question

我正在使用apache POI 3.7。我正在嘗試替換word文檔（docx）中表格列的值。但是，我所做的是不斷追加文檔中當前值的值。但是，如果表列值爲空，它將放置該值。你能給我一些想法如何解決這個問題。以下是我迄今爲止所做的代碼。

在此先感謝。

package test.doc; 
import java.io.FileInputStream; 
import java.io.FileOutputStream; 
import java.io.IOException; 
import java.io.InputStream; 
import java.io.OutputStream; 
import java.util.List; 

import org.apache.poi.xwpf.usermodel.XWPFDocument; 
import org.apache.poi.xwpf.usermodel.XWPFParagraph; 
import org.apache.poi.xwpf.usermodel.XWPFTable; 
import org.apache.poi.xwpf.usermodel.XWPFTableCell; 
import org.apache.poi.xwpf.usermodel.XWPFTableRow; 

public class POIDocXTableTest { 

    public static void main(String[] args)throws IOException { 
     String fileName = "C:\\Test.docx"; 
     InputStream fis = new FileInputStream(fileName); 
     XWPFDocument document = new XWPFDocument(fis); 
     List<XWPFParagraph> paragraphs = document.getParagraphs(); 

     for (int x=0; x<paragraphs.size();x++) 
     { 
      XWPFParagraph paragraph = paragraphs.get(x); 
      System.out.println(paragraph.getParagraphText()); 
     } 
     List<XWPFTable> tables = document.getTables(); 
     for (int x=0; x<tables.size();x++) 
     { 
      XWPFTable table = tables.get(x); 
      List<XWPFTableRow> tableRows = table.getRows(); 
      tableRows.remove(x); 
      for (int r=0; r<tableRows.size();r++) 
      { 
       System.out.println("Row "+ (r+1)+ ":"); 
       XWPFTableRow tableRow = tableRows.get(r); 
       List<XWPFTableCell> tableCells = tableRow.getTableCells(); 
       for (int c=0; c<tableCells.size();c++) 
       { 
        System.out.print("Column "+ (c+1)+ ": "); 
        XWPFTableCell tableCell = tableCells.get(c); 
        //tableCell.setText("TAE"); 
        String tableCellVal = tableCell.getText(); 
        if ((c+1)==2){ 
         if (tableCellVal!=null){ 
          if (tableCellVal.length()>0){ 
           char c1 = tableCellVal.charAt(0); 
           String s2 = "-TEST"; 
           char c2 = s2.charAt(0); 
           String test = tableCell.getText().replace(tableCellVal,s2); 
           tableCell.setText(test); 
          }else{ 
           //tableCell.setText("NULL"); 
          } 
         } 
        } 
        System.out.println("tableCell.getText(" + (c) + "):" + tableCellVal); 
       } 
      } 
      System.out.println("\n"); 
     } 
     OutputStream out = new FileOutputStream(fileName); 
     document.write(out); 
     out.close(); 
    } 
} 

Answer 1

好了，我已經做了類似的東西，以取代由指定的字一個字模板痕跡...：

public DotxTemplateFiller() { 
    String filename = "/poi/ls_Template_modern_de.dotx"; 
    String outputPath = "/poi/output/output" + new Date().getTime() 
      + ".dotx"; 
    OutputStream out = null; 
    try { 
     File file = new File(filename); 
     XWPFDocument template = new XWPFDocument(new FileInputStream(file)); 

     List<XWPFParagraph> xwpfParagraphs = template.getParagraphs(); 
     replaceInParagraphs(xwpfParagraphs); 

     List<XWPFTable> tables = template.getTables(); 
     for (XWPFTable xwpfTable : tables) { 
      List<XWPFTableRow> tableRows = xwpfTable.getRows(); 
      for (XWPFTableRow xwpfTableRow : tableRows) { 
       List<XWPFTableCell> tableCells = xwpfTableRow 
         .getTableCells(); 
       for (XWPFTableCell xwpfTableCell : tableCells) { 
        xwpfParagraphs = xwpfTableCell.getParagraphs(); 
        replaceInParagraphs(xwpfParagraphs); 
       } 
      } 
     } 

     out = new FileOutputStream(new File(outputPath)); 
     template.write(out); 
     out.flush(); 
     out.close(); 
     //System.exit(0); 
    } catch (IOException e) { 
     e.printStackTrace(); 
    } finally { 
     if (out != null) { 
      try { 
       out.close(); 
      } catch (IOException e) { 
       // nothing to do .... 
      } 
     } 
    } 
} 

/** 
* @param xwpfParagraphs 
*/ 
private void replaceInParagraphs(List<XWPFParagraph> xwpfParagraphs) { 
    for (XWPFParagraph xwpfParagraph : xwpfParagraphs) { 
     List<XWPFRun> xwpfRuns = xwpfParagraph.getRuns(); 
     for (XWPFRun xwpfRun : xwpfRuns) { 
      String xwpfRunText = xwpfRun.getText(xwpfRun 
        .getTextPosition()); 
      for (Map.Entry<String, String> entry : replacements 
        .entrySet()) { 
       if (xwpfRunText != null 
         && xwpfRunText.contains(entry.getKey())) { 
        xwpfRunText = xwpfRunText.replaceAll(
          entry.getKey(), entry.getValue()); 
       } 
      } 
      xwpfRun.setText(xwpfRunText, 0); 
     } 
    } 
} 

public static void main(String[] args) { 
    new DotxTemplateFiller(); 
} 

首先我是做定期的段落在MS Word模板和比表格單元格中的段落要多。 希望它對你有所幫助，我希望我能理解你的問題... :-)

祝你好運。

Answer 2

防止段落樣式和找到不同風格的搜索字符串最好的解決方法是這樣的方法：

private long replaceInParagraphs(Map<String, String> replacements, List<XWPFParagraph> xwpfParagraphs) { 
    long count = 0; 
    for (XWPFParagraph paragraph : xwpfParagraphs) { 
     List<XWPFRun> runs = paragraph.getRuns(); 

     for (Map.Entry<String, String> replPair : replacements.entrySet()) {  
     String find = replPair.getKey(); 
     String repl = replPair.getValue(); 
     TextSegement found = paragraph.searchText(find, new PositionInParagraph()); 
     if (found != null) { 
      count++; 
      if (found.getBeginRun() == found.getEndRun()) { 
      // whole search string is in one Run 
      XWPFRun run = runs.get(found.getBeginRun()); 
      String runText = run.getText(run.getTextPosition()); 
      String replaced = runText.replace(find, repl); 
      run.setText(replaced, 0); 
      } else { 
      // The search string spans over more than one Run 
      // Put the Strings together 
      StringBuilder b = new StringBuilder(); 
      for (int runPos = found.getBeginRun(); runPos <= found.getEndRun(); runPos++) { 
       XWPFRun run = runs.get(runPos); 
       b.append(run.getText(run.getTextPosition())); 
      }      
      String connectedRuns = b.toString(); 
      String replaced = connectedRuns.replace(find, repl); 

      // The first Run receives the replaced String of all connected Runs 
      XWPFRun partOne = runs.get(found.getBeginRun()); 
      partOne.setText(replaced, 0); 
      // Removing the text in the other Runs. 
      for (int runPos = found.getBeginRun()+1; runPos <= found.getEndRun(); runPos++) { 
       XWPFRun partNext = runs.get(runPos); 
       partNext.setText("", 0); 
      }       
      } 
     } 
     }  
    } 
    return count; 
    } 

此方法適用於搜索字符串跨越一個以上的運行。被替換的部分從第一次找到的Run中獲取樣式。