經過的時間,如果我有兩排Mysql的共有來自兩個日期
id created start stop
1 28-01-2011 23:00 28-01-2011 23:00 28-01-2011 23:01
2 28-01-2011 23:10 28-01-2011 23:10 28-01-2011 23:11
我可以運行什麼查詢來獲取總時間爲一個日期,所以28-01-2011的總時間爲2分鐘。
這可能嗎?
經過的時間,如果我有兩排Mysql的共有來自兩個日期
id created start stop
1 28-01-2011 23:00 28-01-2011 23:00 28-01-2011 23:01
2 28-01-2011 23:10 28-01-2011 23:10 28-01-2011 23:11
我可以運行什麼查詢來獲取總時間爲一個日期,所以28-01-2011的總時間爲2分鐘。
這可能嗎?
以及一個選擇是直截了當:
select sum(unix_timestamp(stop) -
unix_timestamp(start))/60 from table
where date(created) = '28-01-2011';
mysql> select now(), date_add(now(), interval 10 minute);
+---------------------+-------------------------------------+
| now() | date_add(now(), interval 10 minute) |
+---------------------+-------------------------------------+
| 2011-10-04 13:29:56 | 2011-10-04 13:39:56 |
+---------------------+-------------------------------------+
1 row in set (0.01 sec)
mysql> select sum(unix_timestamp(now()) -
unix_timestamp(date_add(now(), interval 10 minute)));
+----------------------------------------------------------------------------------+
| sum(unix_timestamp(now()) - unix_timestamp(date_add(now(), interval 10 minute))) |
+----------------------------------------------------------------------------------+
| -600 |
+----------------------------------------------------------------------------------+
1 row in set (0.00 sec)
mysql> select sum(unix_timestamp(now()) -
unix_timestamp(date_add(now(), interval 10 minute)))/60 ;
+---------------------------------------------------------------------------------------+
| sum(unix_timestamp(now()) - unix_timestamp(date_add(now(), interval 10 minute)))/60 |
+---------------------------------------------------------------------------------------+
| -10.0000 |
+---------------------------------------------------------------------------------------+
1 row in set (0.00 sec)
做那些列有型'datetime'或者是他們在這個格式字符串: 'DD-MM-YYYY HH:MM'? –
列類型:時間戳。 @MarkByers – benhowdle89