如何在python中獲取當前ec2實例的公共ip？

Question

如何在python中獲取當前EC2實例的公有ip地址？

Answer 1

import urllib.request 
urllib.request.urlopen("http://169.254.169.254/latest/meta-data/public-ipv4").read() 

Answer 2

如果您已經使用boto，你也可以使用boto.utils.get_instance_metadata功能。這會調用元數據服務器，收集所有元數據並將其作爲Python字典返回。它也處理重試。

Answer 3

def console(cmd): 
    p = Popen(cmd,shell=True,stdout=PIPE) 
    out,err = p.communicate() 
    dir_list = out.split('\n') 
    return (dir_list) 
ip = console("http://169.254.169.254/latest/meta-data/public-ipv4") 
print ip 

Answer 4

import requests 
ip = requests.get("http://169.254.169.254/latest/meta-data/public-ipv4").content 

Answer 5

下面的方法將返回公共IP或您的EC2實例的彈性IP地址（注意：如果EIP地址與您的EC2實例相關聯，那麼公共IP地址實際上是釋放）。

這對於Django項目特別有用，因爲您可以在settings.py腳本中將IP地址附加到ALLOWED_HOSTS。

• 安裝PyCurl

  pip install pycurl 
  

• Python 3中

  import pycurl 
  from io import BytesIO 
  
  # Determine Public IP address of EC2 instance 
  buffer = BytesIO() 
  c = pycurl.Curl() 
  c.setopt(c.URL, 'checkip.amazonaws.com') 
  c.setopt(c.WRITEDATA, buffer) 
  c.perform() 
  c.close() 
  body = buffer.getvalue() 
  # Body is a byte string, encoded. Decode it first. 
  print (body.decode('iso-8859-1').strip()) 
  

• 的Python 2

  import pycurl 
  from StringIO import StringIO 
  
  buffer = StringIO() 
  c = pycurl.Curl() 
  c.setopt(c.URL, 'checkip.amazonaws.com') 
  c.setopt(c.WRITEDATA, buffer) 
  c.perform() 
  c.close() 
  
  body = buffer.getvalue() 
  # Body is a string in some encoding. 
  # In Python 2, we can print it without knowing what the encoding is. 
  print (body) 
  

歡呼。