MySQL的日期範圍：在同一日期之間的出現

Question

我有一個具有payment_date行的MySQL表。 我從日期X和日期Y得到的行。 我想打印每個日期的出現次數。

例如：

payment_date 
2011-07-25 
2011-07-24 
2011-07-25 
2011-06-13 

我需要返回在：

2011-07-25 got 2 payments 
2011-07-24 got 1 payments 
2011-06-13 got 1 payment 

有了這個信息，我正在做一個情節，與X軸：日期，Y軸：數的付款。

我的查詢現在是：

SELECT * 
FROM table_pay 
WHERE DATE_FORMAT(payment_date, '%m/%d/%Y') 
BETWEEN '$payment_date_from' 
AND 
DATE '$payment_date_to' 
GROUP BY DATE(payment_date) 

[不知道!!!!]

任何幫助，請？

Answer 1

SELECT 
payment_date,count(*) as tot 
FROM table_pay 
WHERE payment_date 
BETWEEN '$payment_date_from' 
AND 
'$payment_date_to' 
GROUP BY payment_date 
order by tot desc 

Answer 2

試試這個，不能測試它現在那麼請回復是否管用，你是希望

SELECT DATE_FORMAT(payment_date, '%Y-%m-%d'), COUNT(*) 
FROM table_pay 
WHERE payment_date BETWEEN '$payment_date_from' AND '$payment_date_to' 
GROUP BY payment_date 

Answer 3

我會使用類似下面的查詢（假設PAYMENT_DATE是一個日期） ：

Select payment_date, count(*) as paymentcount from table_pay where payment_date between 'startdate' and 'enddate' group by payment_date