如何從呼叫日誌中獲得3首號碼

Question

如何根據撥打號碼的總持續時間從CallLog獲得前三位號碼？

例如，給定這些調用/持續時間：

• 0123-2323 3分鐘
• 0123-2323爲59分鐘
• 3232-3210 15分鐘

總爲0123-2323是totalmin=62。對於3232-3210，它是totalmin=15。

我試過這段代碼：

private String getCallDetails(){ 
    StringBuffer sb = new StringBuffer(); 
    Cursor managedCursor = managedQuery(CallLog.Calls.CONTENT_URI, null, null, null, null); 
    int number = managedCursor.getColumnIndex(CallLog.Calls.NUMBER); 
    int type = managedCursor.getColumnIndex(CallLog.Calls.TYPE); 
    int date = managedCursor.getColumnIndex(CallLog.Calls.DATE); 
    int duration = managedCursor.getColumnIndex(CallLog.Calls.DURATION); 
    sb.append("Call Details :"); 
    while (managedCursor.moveToNext()){ 
     String phNumber = managedCursor.getString(number); 
     String callType = managedCursor.getString(type); 
     String callDate = managedCursor.getString(date); 
     Date callDayTime = new Date(Long.valueOf(callDate)); 
     String callDuration = managedCursor.getString(duration); 
     String dir = null; 
     int dircode = Integer.parseInt(callType); 
     switch (dircode) { 
     case CallLog.Calls.OUTGOING_TYPE: 
      dir = "OUTGOING"; 
      break; 
     case CallLog.Calls.INCOMING_TYPE: 
      dir = "INCOMING"; 
      break; 
     case CallLog.Calls.MISSED_TYPE: 
      dir = "MISSED"; 
      break; 
     } 
     sb.append("\nPhone Number:--- " + phNumber + " \nCall Type:--- " 
       + dir + " \nCall Date:--- " + callDayTime 
       + " \nCall duration in sec :--- " + callDuration); 
     sb.append("\n----------------------------------"); 
    } 
    managedCursor.close(); 
    return sb.toString(); 
} 

Answer 1

創建地圖和排序。根據通話時間獲取您的聯繫人，並獲得您的前3名聯繫人。

cc1=0; 
Map<String, Integer> sortedMapa = sortByComparator(topsmstreemap, DESC); 
for (Map.Entry<String, Integer> entry : sortedMapDeses.entrySet()) 
{ 
if(cc1<3) 
{cc1++; 
}