Python套接字接收雙倍

Question

我需要一個python程序來使用TCP連接（到另一個程序）來檢索9個字節的集合。

九個字節中的第一個表示一個字符，其餘表示一個字符。

如何從python套接字中提取此信息？我需要手動執行數學轉換流數據還是有更好的方法？

Answer 1

看看蟒蛇struct

http://docs.python.org/library/struct.html

因此，像

from struct import unpack 

unpack('cd',socket_read_buffer) 

--> ('c', 3.1415) 

小心字節序。

Answer 2

如果客戶端和服務器都用Python編寫的，我建議你用鹹菜。它可以讓你將python變量轉換爲字節，然後將它們轉換爲原始類型的python變量。

#SENDER 
 
import pickle, struct 
 

 
#convert the variable to bytes with pickle 
 
bytes = pickle.dumps(original_variable) 
 
#convert its size to a 4 bytes int (in bytes) 
 
#I: 4 bytes unsigned int 
 
#!: network (= big-endian) 
 
length = struct.pack("!I", len(bytes)) 
 
a_socket.sendall(length) 
 
a_socket.sendall(bytes)

#RECEIVER 
 
import pickle, struct 
 

 
#This function lets you receive a given number of bytes and regroup them 
 
def recvall(socket, count): 
 
    buf = b"" 
 
    while count > 0: 
 
     newbuf = socket.recv(count) 
 
     if not newbuf: return None 
 
     buf += newbuf 
 
     count -= len(newbuf) 
 
    return buf 
 

 

 
length, = struct.unpack("!I", recvall(socket, 4)) #we know the first reception is 4 bytes 
 
original_variable = pickle.loads(recval(socket, length))