顯示隨機數和排序

Question

我在這裏打我的同胞，我的同胞。有沒有一種方法可以生成隨機數字，然後指出它們是正面還是負面？

我嘗試使用if語句，但正如您知道一旦它遇見if它不會去else。

請保持您的代碼簡單，讓任何人都能理解正在發生的事情，或者至少說明代碼中發生了什麼。

我該如何解決這個錯誤？

Random rnd = new Random(); 

Console.WriteLine("\n5 random integers from -100 to 100:"); 
for (int X = 1; X <= 5; X++) 
{ 
    if (X >= 0) 
    { 
     Console.WriteLine("These are the positive numbers: {0}", rnd.Next(0, 100)); 
    } 
    else 
    { 
     Console.WriteLine("These are the negative numbers: {0}", rnd.Next(-100, 0)); 
    } 
} 
Console.ReadLine(); 

Answer 1

請嘗試以下代碼...不要比較X;你必須比較隨機數。

Random rnd = new Random(); 

Console.WriteLine("\n5 random integers from -100 to 100:"); 
for (int X = 1; X <= 5; X++) 
{ 
    int y = rnd.Next(-100, 100); 
    if (y >= 0) 
    { 
     Console.WriteLine("These are the positive numbers: {0}", y.ToString()); 
    } 
    else 
    { 
     Console.WriteLine("These are the negative numbers: {0}", y.ToString()); 
    } 
} 
Console.ReadLine(); 

Answer 2

您正在查看x的值。它將始終保持積極。嘗試在您的循環中：

int i = rnd.Next(-100, 100); 

if (i >= 0) 
    //It is positive 
else 
    //It is negative 

Answer 3

這將做的工作：

Random rnd = new Random(); 
int randomNumber = rnd.Next(-100, 100); 

if (randomNumber >= 0) 
    Console.WriteLine("Positive (with Zero)"); 
else 
    Console.WriteLine("Negative"); 

Answer 4

我認爲這會做你正在尋找什麼：

public static void Main(string[] args) 
{ 
     var rnd = new Random(); 
     Console.WriteLine("\n5 random integers from -100 to 100:"); 
     List<int> random = new List<int>(); 

     for (int X = 1; X <= 5; X++) 
     { 
      random.Add(rnd.Next(-100, 100)); 
     } 

     Console.WriteLine("These are the positive numbers:"); 
     foreach (int number in random) 
     { 
      if (number >= 0) 
      { 
       Console.WriteLine(number); 
      } 
     } 

     Console.WriteLine("These are the negative numbers:"); 
     foreach (int number in random) 
     { 
      if (number < 0) 
      { 
       Console.WriteLine(number); 
      } 
     } 

     Console.ReadLine(); 
    } 

這將打印出5個號碼，並讓他們在結果集顯示如下：

Answer 5

Random rnd = new Random(); 

Console.WriteLine("\n5 random integers from -100 to 100:"); 
for (int X = 1; X <= 5; X++) 
{ 
    int Y = rnd.Next(-100, 100); 

    if (Y > 0) 
    { 
     Console.WriteLine("These are the positive numbers: {0}", Y); 
    } 
    else 
    { 
     Console.WriteLine("These are the negative numbers: {0}", Y); 
    } 
} 

Answer 6

使用continue大約是另一種方式：

Random rnd = new Random(); 
Console.WriteLine("\n5 random integers from -100 to 100:"); 
for (int X = 1; X <= 5; X++) 
{ 
    int y = rnd.Next(-100, 100); 
    if (y < 0) 
    { 
     Console.WriteLine("These are the negative numbers: {0}", y); 
     continue; 
    } 
    Console.WriteLine("These are the positive numbers: {0}", y); 
} 
Console.ReadLine();