2016-04-26 83 views
0

我有一個簡單的問題。我所需要做的就是從選定的組合框項目中獲取數組信息。我知道關於combobox.selectedindex但這不是我的問題。我需要檢索數組信息,所以一旦我選擇學生名稱,它會顯示他們的原始成績和彎曲的字母等級。我已經完成了數學,除了這個之外,我已經完成了所有的工作。這是我的代碼。從選定的組合框項目獲取陣列信息。

 Private Sub OpenToolStripMenuItem_Click(sender As Object, e As EventArgs) Handles OpenToolStripMenuItem.Click 

    Dim Line_String As String 

    Dim ArraySize_Integer As Integer = 0 
    Dim Grades_StreamReader As IO.StreamReader 
    Dim i As Integer = 0 
    Dim GradesFile_String As String = "Grades.txt" 'To hold the filename for opening 
    Dim DialogResponse As DialogResult 
    Dim x_Integer As Integer 
    Dim Mean_Decimal As Double = 0 
    Dim Total_Integer As Double = 0 
    Dim sum As Double 
    Dim stDev As Double 
    Dim x As Integer 
    Dim y As Integer 
    Dim orgScore As Integer 


    'Prompt to open the file 

    'Set the initial folder to display 
    OpenFileDialog1.InitialDirectory = IO.Directory.GetCurrentDirectory 


    'Open the file 
    With OpenFileDialog1 
     'Begin in the current folder 
     .InitialDirectory = Directory.GetCurrentDirectory() 
     .FileName = "Grades.txt" 
     .Title = "Select File or Directory for File" 
     'Filter to show only .txt files 
     OpenFileDialog1.Filter = "Text Files (*.txt)|*.txt|All Files (*.*)|*.*" 
     'Display the open file dialog box 
     DialogResponse = .ShowDialog() 
    End With 
    'Get the filename 
    GradesFile_String = OpenFileDialog1.FileName 

    'Connect to the file 
    Grades_StreamReader = IO.File.OpenText(GradesFile_String) 
    'Read the file into a structure array until it runs out of data 
    Do Until Grades_StreamReader.Peek = -1 
     'Raed the data 
     Line_String = Grades_StreamReader.ReadLine 
     'Split the line into the fields 
     StringArray_String = Line_String.Split(","c) 
     'Dynamically size the array of structures 
     ReDim Preserve StudentData_Person(ArraySize_Integer) 
     'Assign the fields to the structure, trimming the space 
     StudentData_Person(ArraySize_Integer).Name_String = StringArray_String(0).Trim 
     StudentData_Person(ArraySize_Integer).Grade_String = StringArray_String(1).Trim 
     'Increment for the next array element 
     ArraySize_Integer += 1 
     'Populate the combo box 
     Students_ComboBox.Items.Add(StringArray_String(0)) 

    Loop 
    'Close the file 
    Grades_StreamReader.Close() 

    'Count the scores 
    'Convert from String to Integer 
    Scores_TextBox.Text = ArraySize_Integer.ToString 



    'Calculate the mean 

    If StudentData_Person.Length > 0 Then 
     For x_Integer = 0 To StudentData_Person.Length - 1 
      Total_Integer += CInt(StudentData_Person(x_Integer).Grade_String) 
     Next 
     Mean_Decimal = Total_Integer/StudentData_Person.Length 
    End If 
    Mean_TextBox.Text = Mean_Decimal.ToString 

    'Calculate the Standard Deviation 

    If StudentData_Person.Length > 0 Then 
     For x = 0 To StudentData_Person.Length - 1 
      sum += ((CInt(StudentData_Person(x).Grade_String) - Mean_Decimal)^2) 
     Next 
     stDev = Math.Round(Math.Sqrt(sum/(x - 1)), 2) 

    End If 
    stDev_TextBox.Text = stDev.ToString 

    'Get information from ComboBox Selected Entry 
    Students_ComboBox.SelectedIndex 

    'Determine letter grade 
    For y = 0 To StudentData_Person.Length 
     If CInt(StudentData_Person(x).Grade_String) >= Mean_Decimal + (1.5 * stDev) Then 
      CurvedGrade_TextBox.Text = "A" 
     End If 
     If (Mean_Decimal + (0.5 * stDev)) <= CInt(StudentData_Person(x).Grade_String) And CInt(StudentData_Person(x).Grade_String) < (Mean_Decimal + (1.5 * stDev)) Then 
      CurvedGrade_TextBox.Text = "B" 
     End If 
     If (Mean_Decimal - (0.5 * stDev)) <= CInt(StudentData_Person(x).Grade_String) And CInt(StudentData_Person(x).Grade_String) < (Mean_Decimal + (1.5 * stDev)) Then 
      CurvedGrade_TextBox.Text = "C" 
     End If 
     If (Mean_Decimal - (1.5 * stDev)) <= CInt(StudentData_Person(x).Grade_String) And CInt(StudentData_Person(x).Grade_String) < (Mean_Decimal + (1.5 * stDev)) Then 
      CurvedGrade_TextBox.Text = "D" 
     End If 
     If CInt(StudentData_Person(x).Grade_String) < (Mean_Decimal - (1.5 * stDev)) Then 
      CurvedGrade_TextBox.Text = "F" 
     End If 
    Next 
End Sub 
End Class 

我還要再需要從這個檢索信息並計算他們的分數給出,並將它推回給該文本框,我可以做的。

請問我只是做

originalscore_textbox.text = StudentData_Person(SelectedIndex) 
    curvedgrade_textbox.text = 'something like what's above this line 

或類似的東西,我知道這肯定是不對的,我只是你們展示我的思維理念。任何問題,請問我會盡我所能解釋他們。但這實際上就是我所需要的,我已經完成了我的程序哈哈。

回答

0

如果您發佈瞭如何定義StudentData_Person會很有幫助。

我建議爲StudentData_Person添加一個新的Curved_String字段。並在計算出彎曲坡度時填充它。然後你就做。

originalscore_textbox.text = StudentData_Person(SelectedIndex).Grade_String 
curvedgrade_textbox.text = StudentData_Person(SelectedIndex).Curved_String 
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