保存在.txt文件中的整數輸入（Java）

Question

我試圖讓我輸入的整數被寫入文本文件，但是我編輯代碼我的記事本吐出我的整數作爲無稽之談。示例：

Integer輸入：java.util.Scanner [delimiters = \ p {javaWhitespace} +] [position = 1] [match valid = true] [need input = false] [source closed = false] [skipped =假] ...

我相信我的問題是在我標有「*」的行。我將如何去解決這個問題？我相信它與「String.valueOf（input）」行有關。完整的代碼鏈接如下！

for (int i = 0 ; i < 10 ; i++) { 
      System.out.printf("Please enter integer %d: ", i+1); 
      numbers[i] = input.nextInt(); 

      { 
       try 
       { 
        *output.format("Integer inputted: %s%n", String.valueOf(input)); 
       } 
       catch (FormatterClosedException formatterClosedexception) 
       { 
        System.err.println("Error writing to the file. Terminating."); 
        break; 
       } 
       catch (NoSuchElementException elementException) 
       { 
        System.err.println("Invalid input. Please try again."); 
        input.nextLine(); 
       } 

http://pastebin.com/yV6dhSMt

Answer 1

你可以用它來在寫入文件：

PrintWriter writer = new PrintWriter(fileName); 
writer.println("1"); 
writer.println("2"); 
writer.close(); 

這從該文件中讀取：

String line, newLine;   // Variable to store a line and to check for a new line 
    String[] splited;    // Variable to split text 
    int lines = 0;    // Variable to check how many lines in a file 

    Scanner myReader = new Scanner(new File(fileName)); 
    BufferedReader bufferedReader = new BufferedReader(new FileReader(fileName)); 

    Numbers[] numbers = new numbers[2]; 

    while ((line = bufferedReader.readLine()) != null) { 
    lines++; 
    for (int i = 1 ; i < 2 ; i++) { 
     while (myReader.hasNextLine()) { 
      newLine = myReader.nextLine(); 
      splited = newLine.split(","); 
      numbers[i] = Integer.parseInt(splited[i]); 
     } 
    } 
    } 

    myReader.close(); 

我剛纔寫的這裏，但從我記得這是我是如何做到的。