怎麼看多少行的多個SQL返回查詢

Question

我有這個代碼就可以了PHP腳本：

<?php 
    $sql="SELECT * from reminders where duedate < DATE(now()) and dismissed = '' "; 
    $rs=mysql_query($sql,$conn) or die(mysql_error()); 
    if(mysql_num_rows($rs) > 0) 
    { 
     ?> 
     <div class="box">There are overdue reminders. <a href="/admin/reminders/reminders.php?action=overdue">Click Here to view</a></div> 
     <script type="text/javascript"> 
     window.onload = function() 
     { 
      var answer = confirm("You have Overdue Reminders. Would you like to view them?") 
      if (answer) 
      { 
       window.location = "/admin/reminders/reminders.phpaction=overdue"; 
      } 
     } 
     </script> 
     <?php 
    } 
    $sql="SELECT * from reminders where duedate = DATE(now()) and dismissed = '' "; 
    $rs=mysql_query($sql,$conn) or die(mysql_error()); 
    if(mysql_num_rows($rs) > 0) 
    { 
     ?> 
     <div class="box">There are reminders due today. <a href="/admin/reminders/reminders.php?action=due">Click Here to view</a></div> 
     <script type="text/javascript"> 
     window.onload = function() 
     { 
      var answer = confirm("You have Reminders Due today. Would you like to view them?") 
      if (answer) 
      { 
       window.location = "/admin/reminders/reminders.php?action=due"; 
      } 
     } 
     </script> 
     <?php 
    } 
    ?> 
    <!-- list cstomers who've gone over their allocation --> 
    <?php 
    //sql to list all customers with support this month 
    $startdate=date("Y-m-01 00:00:00"); 
    $enddate=date("Y-m-t 23:59:59"); 
    $sql="SELECT tickets.company, tickets.ticketnumber, SUM(TIMEDIFF(ticket_updates.timeend, ticket_updates.timestart)) /100 AS support_time_used 
    FROM tickets, ticket_updates 
    WHERE tickets.ticketnumber = ticket_updates.ticket_seq and tickets.datetime>'".$startdate."' and tickets.datetime<'".$enddate."' 
    GROUP BY tickets.company 
    ORDER BY tickets.company ASC"; 
    $rs=mysql_query($sql,$conn) or die (mysql_error()); 
    while($result=mysql_fetch_array($rs)) 
    { 
     //loop through all support companies and if they have more than their allocated number of minutes, then show them up 
     //first, get number of minutes in support allocation 
     $sql="select company,support_minutes from customer where sequence = '".$result["company"]."' "; 
     $rs2=mysql_query($sql,$conn) or die(mysql_error()); 
     $result2=mysql_fetch_array($rs2); 
     if($result2["support_minutes"] != '0') 
     { 
      if ($result["support_time_used"]>$result2["support_minutes"]) 
      { 
       $used_minutes = round($result["support_time_used"]); 
       $used_hours = $used_minutes/60; 

       $total_minutes = round($result2["support_minutes"],0); 
       $total_hours = $total_minutes/60; 
       //check whether ti display minutes or hours 
       if($used_hours < 1) 
       { 
        //customer has exceeded inclusive minutes/hours 
        //display minutes 
        echo '<div class="box"><strong><a href="/admin/customer/editcustomer.php?seq='.$result2["sequence"].'">'.$result2["company"].'</a> have used '.$used_minutes.' minutes of their '.$total_hours.' support hours this month</strong></div>'; 
       } 
       elseif($used_hours > 1) 
       { 
        //customer has exceeded inclusive minutes/hours 
        //display hours 
        echo '<div class="box"><strong><a href="/admin/customer/editcustomer.php?seq='.$result2["sequence"].'">'.$result2["company"].'</a> have used '.$used_hours.' hours of their '.$total_hours.' support hours this month</strong></div>'; 
       } 
      } 
     } 
    } 
    ?> 
    <!-- END --> 
    <!-- Display open service issues/status updates --> 
    <?php 
    $sql="SELECT * from servicestatus where status<>'Closed' "; 
    $rs=mysql_query($sql,$conn) or die (mysql_error()); 
    $count = mysql_num_rows($rs); 
    $result=mysql_fetch_array($rs); 
    if(mysql_num_rows($rs) > 0) 
    { 
     echo '<div class="box"><strong>There are currently '.$count.' <a href="/admin/servicestatus/viewservicestatus.php?status=Open">Open Service Issues</a></strong></div>'; 
    } 
    ?> 
    <!-- END --> 
    <!-- Display not viewed customer notes (added by call answering) --> 
    <?php 
    $sql="SELECT * from customer_notes where viewed = 'no' "; 
    $rs=mysql_query($sql,$conn) or die (mysql_error()); 
    $count = mysql_num_rows($rs); 
    if(mysql_num_rows($rs) > 0) 
    { 
     while($result=mysql_fetch_array($rs)) 
     { 
      $sql2="SELECT * from customer where sequence = '".$result["customer"]."' "; 
      $rs2=mysql_query($sql2,$conn) or die(mysql_error()); 
      $result2=mysql_fetch_array($rs2); 

      echo '<div class="box"><strong>There are Customer Notes for '.$result2["company"].' that have\'t been viewed. <a href="javascript: void(0)" onclick="popup(\'/admin/customer/unviewed-notes.php?seq='.mysql_real_escape_string($result["sequence"]).'\')">Click Here</a></strong></div>'; 
     } 
    } 
    ?> 

有一些查詢不同的表等許多SQL查詢，我知道你可以使用if(mysql_num_rows($rs) == 0) { echo 'something here'; }但那隻會是其中一個查詢。查看NONE查詢是否返回任何行以顯示消息的最佳方法是什麼？

Answer 1

在腳本的開始，初始化變量：

$something_found = false; 

內。然後每個if(mysql_num_rows($rs) > 0)塊，這樣做：

$something_found = true; 

然後在全部完成後測試$something_found。

Answer 2

您可以使用：

$sql="SELECT COUNT('id') as COUNT_ID,* from customer_notes where viewed = 'no' "; 

//.... 

if($result['COUNT_ID'] > 0) 
{ 
    .... 
}