我有以下MySQL查詢;從MySQL查詢迴應單個結果
SELECT *, @rownum := @rownum + 1 from
(
SELECT (display_name) 'Author',
IFNULL(ROUND(SUM(balance.meta_value),2),2) 'Balance'
FROM posts p
JOIN users u
ON p.post_author = u.ID
JOIN postmeta odd ON p.ID = odd.post_id AND odd.meta_key = 'odd' AND odd.meta_value >= 1.5
LEFT JOIN postmeta balance
ON p.ID = balance.post_id AND balance.meta_key = 'balance'
WHERE p.post_status = 'publish' and p.post_author = 'User1'
GROUP BY u.ID
ORDER BY Balance DESC
)x, (SELECT @rownum := 0) r
它產生下表;
Users Balance @rownum := 0 @rownum := @rownum + 1
User1 5.88 0 1
User2 -23.41 0 2
我怎樣才能回聲針對第一用戶的最後一列的值(其中,[@rownum:= @rownum + 1] = 1
由於
也許取整排與mysql_fetch_array()和只取最後一個元素此數組中? – chao
@chao - 你能給我一個代碼的例子嗎 – qebas