<?php
$player[] = array();
$team_id = $_SESSION['tid'];
$team_pids = $con->prepare("SELECT p_id FROM players_to_team WHERE t_id = ?");
$team_pids->bindParam(1,$team_id);
$team_pids->execute();
while($info = $team_pids->fetch(PDO::FETCH_ASSOC))
{
$player[] = $info['p_id'];
echo $info['p_id'];
}
$pl_1 = $player[0];
.
.
.
$pl_10 = $player[9];
echo $player[0]; //notice here
echo $pl_1; //notice here
?>
<table>
$query = $con->prepare("SELECT role,name,value FROM players WHERE p_id = '".$pl_1."'");
// notice here
$query->execute();
while($result = $query->fetch(PDO::FETCH_ASSOC))
{
echo "<tr>";
echo "<td>".$result['role']."</td>";
echo "<td>".$result['name']."</td>";
echo "<td>".$result['value']."</td>";
}
?>
</tr>
</table>
當我echo $信息數組它可以正常工作,但是當我回聲$ player數組或$ $ pl_1變量或$結果數組值$ Notice to appear ... Array to string conversion and o/p不顯示。 爲什麼?通知:數組到字符串轉換在PHP
因爲兩者都是數組而不是字符串。而不是'echo'使用print_r($ player [0]);和print_r($ pl_1);看陣列。 –
你可以在任何變量上使用[var_dump](http://php.net/var_dump)來查看變量TYPE以及它的內容,以更好地理解你的代碼中的變量賦值。 – Latheesan
[參考 - 這個錯誤在PHP中意味着什麼?](http://stackoverflow.com/questions/12769982/reference-what-does-this-error-mean-in-php) – naththedeveloper