條條框框思考了一下,如果它是允許的,只是讓每個30分鐘時間最早的行,然後我有一個可行的解決方案。
注意事項:
- 我認爲在這一點上你的數據可能會去追溯到30年。 1300萬間隔接近配置表的配置方式的極限,所以如果你超過16密爾,你需要進行修改
- 您可能需要將CTE分解爲臨時表並添加索引以獲得良好的性能數據:-)
-
--setup data
declare @t table (VID int, [Datetime] datetime);
insert @t values
(1, '1986-01-01 00:00'), --very early year
(1, '2016-01-01 00:10'),
(1, '2016-01-01 00:12'),
(1, '2016-01-01 00:25'),
(2, '2016-01-01 00:40'),
(4, '2016-01-01 01:00'),
(4, '2016-01-01 02:13'),
(6, '2016-01-01 02:23'),
(7, '2016-01-01 02:25'),
(8, '2016-01-01 02:49'),
(9, '2016-01-01 02:59'),
(9, '2016-01-01 03:01'),
(9, '2016-01-01 03:09'),
(9, '2016-01-01 03:24'),
(9, '2016-01-01 04:05');
select * from @t order by VID, [Datetime];
--select datediff(MI, (select min([Datetime]) from @t), (select max([Datetime]) from @t)); --15778325 records in 30 years - handled by t4 x t4 x t4 in tally generator
-- Tally generator courtesy of http://www.sqlservercentral.com/blogs/never_say_never/2010/03/19/tally_2D00_table_2D00_cte/
-- Tally Table CTE script (SQL 2005+ only)
-- You can use this to create many different numbers of rows... for example:
-- You could use a 3 way cross join (t3 x, t3 y, t3 z) instead of just 2 way to generate a different number of rows.
-- The # of rows this would generate for each is noted in the X3 comment column below.
-- For most common usage, I find t3 or t4 to be enough, so that is what is coded here.
-- If you use t3 in ‘Tally’, you can delete t4 and t5.
; WITH
-- Tally table Gen Tally Rows: X2 X3
t1 AS (SELECT 1 N UNION ALL SELECT 1 N), -- 4 , 8
t2 AS (SELECT 1 N FROM t1 x, t1 y), -- 16 , 64
t3 AS (SELECT 1 N FROM t2 x, t2 y), -- 256 , 4096
t4 AS (SELECT 1 N FROM t3 x, t3 y), -- 65536 , 16,777,216
t5 AS (SELECT 1 N FROM t4 x, t4 y), -- 4,294,967,296, A lot
Tally AS (SELECT ROW_NUMBER() OVER (ORDER BY (SELECT NULL)) N
FROM t4 x, t4 y, t4 z), -- Change the t3's to one of the other numbers above for more/less rows
--generate time values
Intervals as (
select t.N - 1 interval,
dateadd(mi, (t.N - 1) * 30, min_date.min_date) interval_start,
dateadd(mi, (t.N) * 30, min_date.min_date) next_interval_start
from (
select min([Datetime]) min_date
from @t
) min_date
join Tally t
on t.N <= datediff(MI, (select min([Datetime]) from @t), (select max([Datetime]) from @t))/30 + 1
),
--join intervals to data tables
Intervaled_data as (
select *, row_number() over (partition by i.interval order by t.[Datetime]) row_num
from @t t
join Intervals i
on t.[Datetime] >= i.interval_start and t.[Datetime] < i.next_interval_start
)
select i.VID, i.[Datetime]
from Intervaled_data i
where i.row_num = 1
order by i.VID, i.[Datetime];
古怪的更新有要求非常具體名單爲它才能正常工作。這也是無證的行爲,因此它可能會或可能不總是爲你工作。然而,傑夫·莫德在這個話題上有一篇很棒的文章。 http://www.sqlservercentral.com/articles/T-SQL/68467/缺點是我不認爲這是你想要的。看起來你想在每個30分鐘窗口中獲得最低的日期時間值。你可以在這裏用分區使用ROW_NUMBER。如果沒有人提供答案,我會在會議結束後嘗試工作。 –
@SeanLange:謝謝! – user3150002
這樣的時代我真的很希望我的工作能夠在一起,並在2008年取得成功。我感到領先/滯後的答案,但無法在工作中進行測試。 –