如何從UInt32數組轉換爲字節數組？

Question

This只有問題反之亦然。現在我得到這樣的：

UInt32[] target; 

byte[] decoded = new byte[target.Length * 2]; 
Buffer.BlockCopy(target, 0, decoded, 0, target.Length); 

這是不行的，我得到陣列充滿0x00。

Answer 1

我建議像下面這樣：

UInt32[] target; 

//Assignments 

byte[] decoded = new byte[target.Length * sizeof(uint)]; 
Buffer.BlockCopy(target, 0, decoded, 0, decoded.Length); 

見代碼：

uint[] target = new uint[] { 1, 2, 3 }; 

//Assignments 

byte[] decoded = new byte[target.Length * sizeof(uint)]; 
Buffer.BlockCopy(target, 0, decoded, 0, decoded.Length); 

for (int i = 0; i < decoded.Length; i++) 
{ 
    Console.WriteLine(decoded[i]); 
} 

Console.ReadKey(); 

另見：

• Size of values
• Int Array to Byte Array
• BlockCopy MSDN

Answer 2

可以使用BitConverter.GetBytes方法用於將unit到byte

Answer 3

你需要多個由4來創建byte陣列，由於UInt32是4個字節（32位）。但是，使用BitConverter並填寫byte的列表，如果需要，您可以稍後創建一個陣列。

UInt32[] target = new UInt32[] { 1, 2, 3 }; 
byte[] decoded = new byte[target.Length * 4]; //not required now 
List<byte> listOfBytes = new List<byte>(); 
foreach (var item in target) 
{ 
    listOfBytes.AddRange(BitConverter.GetBytes(item)); 
} 

如果你需要數組，那麼：

byte[] decoded = listOfBytes.ToArray(); 

Answer 4

你的代碼中有幾個錯誤：

UInt32[] target = new uint[] { 1, 2, 3, 4 }; 

// Error 1: 
// You had 2 instead of 4. Each UInt32 is actually 4 bytes. 
byte[] decoded = new byte[target.Length * 4]; 

// Error 2: 
Buffer.BlockCopy(
    src: target, 
    srcOffset: 0, 
    dst: decoded, 
    dstOffset: 0, 
    count: decoded.Length // You had target.Length. You want the length in bytes. 
); 

這應該得到你期待什麼。

Answer 5

試試這個代碼。這個對我有用。

UInt32[] target = new UInt32[]{1,2,3}; 
    byte[] decoded = new byte[target.Length * sizeof(UInt32)]; 
    Buffer.BlockCopy(target, 0, decoded, 0, target.Length*sizeof(UInt32)); 

    foreach(byte b in decoded)  
    { 
     Console.WriteLine(b); 
    }