有我的Ajax請求發生在Django

Question

文本我有跟隨按鈕，它的工作原理是使用Ajax {{ total_followers }}作品以及通過增加或在點擊減小之前刷新頁面，但遵循和取消關注按鈕時才改變我刷新整個頁面是什麼，我不想

我的觀點

@ajax_required 
@require_POST 
@login_required 
def user_follow(request): 
    user_id = request.POST.get('id') 
    action = request.POST.get('action') 
    if user_id and action: 
     try: 
      user = User.objects.get(id=user_id) 
      if action == 'follow': 
       Contact.objects.get_or_create(user_from=request.user,user_to=user) 
      else: 
       Contact.objects.filter(user_from=request.user,user_to=user).delete() 
      return JsonResponse({'status':'ok'}) 
     except User.DoesNotExist: 
      return JsonResponse({'status':'ok'}) 
    return JsonResponse({'status':'ok'}) 

我的HTML

{% extends 'base.html' %} 
{% load thumbnail %} 

{% block title %}{{ user.get_full_name }}{% endblock %} 

{% block content %} 
<h1>{{ user.get_full_name }}</h1> 
<div class="profile-info"> 
    {% thumbnail user.profile.photo '180x180' crop='100%' as im %} 
    <img src="{{ im.url }}" alt="profile photo"> 
    {% endthumbnail %} 
</div> 
{% with total_followers=user.followers.count %} 
<span class="count"> 
    <span class="total">{{ total_followers }}</span> 
    follower{{ total_followers|pluralize }} 
</span> 

<a href="#" data-id='{{ user.id }}' data-action='{% if request.user in user.followers.all %}un{% endif %}follow' class="follow button"> 
    {% if request.user not in user.followers.all %} 
    Follow 
    {% else %} 
    Unfollow 
    {% endif %} 
</a> 

<div id="image-list" class="image-container"> 
    {% include "images/image/list_ajax.html" with images=user.images_created.all %} 
</div> 
{% endwith %} 
{% endblock %} 

{% block domready %} 
$('a.follow').click(function(e){ 
e.preventDefault(); 
$.post('{% url "user_follow" %}', 
{ 
id: $(this).data('id'), 
action: $(this).data('action') 
}, 
function(data){ 
if (data['status'] == 'ok') { 
var previous_action = $('a.follow').data('action'); 
// toggle data-action 
$('a.follow').data('action', 
previous_action == 'follow' ? 'unfollow' : 'follow'); 

// update total followers 
var previous_followers = parseInt(
$('span.count .total').text()); 
$('span.count .total').text(previous_action == 'follow' ? 
previous_followers + 1 : previous_followers - 1); 
} 
} 
); 
}); 
{% endblock %} 

Answer 1

你需要從視圖當你從阿賈克斯打來電話，與以前的更換HTML當前HTML，你將在成功得到（HTML模板代碼動態返回）方法ajax。

關注這個答案 Return JSON response using Django template system

編輯：

做應該有你要更改時調用Ajax請求的HTML代碼模板。

html = render_to_string("yourtemplate.html", context_object) 
return JsonResponse({'status':'ok', 'html':html}) 

模板：

new_html = data['html'] 
    $selector = $('#id of block'); 
    $selector.html(new_html);