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我正在創建一個應用程序,在其中顯示餐桌列表,並且當您單擊其中一個時,它會更詳細地顯示膳食。Xcode TableViewCell推送到ViewController
當我運行它,它會顯示在桌子上吃飯,但是當我點擊了一頓它只是提供了一頓模板,
這裏是我使用的代碼爲我TableViewController顯示項目
private func loadSampleMeals() {
let photo1 = UIImage(named: "Sprite")
let photo2 = UIImage(named: "HotCheetos")
let photo3 = UIImage(named: "Nachos")
guard let meal1 = Meal(name: "Sprite", price: "$1.50", photo: photo1, rating: 0, calories: "Calories: 129", description: "Description: A refreshing lemon-lime soda") else {
fatalError("Unable to instantiate meal1")
}
guard let meal2 = Meal(name: "Hot Cheetos", price: "$1.50", photo: photo2, rating: 0, calories: "Calories: 160", description: "Description: A spicy version of original cheetos") else {
fatalError("Unable to instantiate meal2")
}
guard let meal3 = Meal(name: "Nachos", price: "$1.50", photo: photo3, rating: 0, calories: "Calories: 436", description: "Description: Tortilla chips with a side of smooth nacho cheese") else {
fatalError("Unable to instantiate meal2")
}
meals += [meal1, meal2, meal3]
}
override func prepare(for segue: UIStoryboardSegue, sender: Any?) {
super.prepare(for: segue, sender: sender)
switch(segue.identifier ?? "") {
case "ShowDetail":
guard let mealDetailViewController = segue.destination as? MealViewController else {
fatalError("Unexpected destination: \(segue.destination)")
}
guard let selectedMealCell = sender as? MealTableViewCell else {
fatalError("Unexpected sender: \(sender)")
}
guard let indexPath = tableView.indexPath(for: selectedMealCell) else {
fatalError("The selected cell is not being displayed by the table")
}
let selectedMeal = meals[indexPath.row]
mealDetailViewController.meal = selectedMeal
default:
fatalError("Unexpected Segue Identifier; \(segue.identifier)")
}
}
在代碼中,保護報表應使其顯示在視圖控制器的項目數據,但我得到了默認的錯誤在底部
您是否通過數據,而改變tableview控制器到詳細控制器? –
你可以用你的tableView方法顯示一些代碼,它會告訴我們你正在做什麼 –
刪除頂部導航控制器...在應用程序中應該只有1個導航控制器... –