使用作業ID的點擊計數器

Question

我想表明訪問者使用他們的id從MySQL數據庫中調用了多少次。

以下是頁面job.details.php中的代碼。

<div style="width:900px;"> 
    <div style="float:left; width:200px;"class="ara-form"><header style="font-size:12px; color:#666666; font:Arial, sans-serif; padding:7px;"><?php 

    $result = mysqli_query($conn,"SELECT * FROM job WHERE jobid = '".$_GET['id']."' ORDER BY `CreatedTime` DESC"); 

    $jobdetails = mysqli_fetch_assoc($result); 

    echo '<strong>Job Title</strong></br> '.$jobdetails['positiontitle'].'<hr class="job">'; 
    echo '<strong>Company Name</strong></br> '.$jobdetails['companyname'].'<hr class="job">'; 
    echo '<strong>Location</strong></br> '.$jobdetails['location'].'<hr class="job">'; 
    echo '<strong>Closing Date</strong></br> '.$jobdetails['closingdate'].'<hr class="job">'; 
    echo '<strong>Number of Vacancy</strong></br> '.$jobdetails['numberofvacancy'].'<hr class="job">'; 
    echo '<strong>Job Category</strong></br> '.$jobdetails['jobcategory'].'<hr class="job">'; 
    echo '<strong>Duration</strong></br> '.$jobdetails['duration'].'<hr class="job">'; 
    echo '<strong>Employment Type</strong></br> '.$jobdetails['employmenttype'].'<hr class="job">'; 
    echo '<strong>Salary</strong></br> '.$jobdetails['salary'].'<hr class="job">'; 
    echo '<strong>Timing</strong></br> '.$jobdetails['timing'].'<hr class="job">'; 
    echo '<strong>Nationality</strong></br> '.$jobdetails['nationality'].'<hr class="job">'; 
    echo '<strong>Gender</strong></br> '.$jobdetails['gender'].'<hr class="job">'; 
    echo '<strong>Experience</strong></br> '.$jobdetails['experience'].'<hr class="job">'; 
    echo '<strong>Education</strong></br> '.$jobdetails['education'].'<hr class="job">'; 
    echo '<strong>Gender</strong></br> '.$jobdetails['gender'].'<hr class="job">'; 
    echo '<strong>Gender</strong></br> '.$jobdetails['gender'].'<hr class="job">'; 


?></header></div> 
    <div style="float:left; width:600px;" class="ara-form"> 
    <fieldset style="font-size:12px; color:#666666; font:Arial, sans-serif;"> 
    <?php 

    echo '<p><strong id="ara-form">Company Background</strong></br> '.$jobdetails['background'].'</p></br>'; 
    echo '<p><strong id="ara-form">Job Summary</strong></br> '.$jobdetails['summary'].'</p></br>'; 
    echo '<p><strong id="ara-form">Job Duties and Responsibilities</strong></br> '.$jobdetails['duty'].'</p></br>'; 
    echo '<p><strong id="ara-form">Qualification</strong></br> '.$jobdetails['qualification'].'</p></br>'; 
    echo '<p><strong id="ara-form">Skills</strong></br> '.$jobdetails['skill'].'<hr class="job"></p></br>'; 
    echo '<p><strong id="ara-form">Submission Guideline</strong></br> '.$jobdetails['submission'].'</p></br>'; 
    echo '<p><strong id="ara-form">Words to search this job</strong></br> '.$jobdetails['search'].'</p></br>'; 
    ?> 
    </fieldset></div> 
    <div style="float:left; width:33.4%; background:#ccc;">three</div> 
    <div style="clear:both;"></div> 
</div> 

</div> 

這是我一直在從MySQL被稱爲其ID的工作的一個例子： http://example.com/job/job.details.php?id=171

Answer 1

至於說通過@I可以了Kittenz，它不是一個臨時存儲，並且需要持久性。 我可以建議創建一個表是這樣的：

mysql> create table `pageviews`(
-> `id` INT UNSIGNED NOT NULL AUTO_INCREMENT PRIMARY KEY, 
-> `job_id` int, 
-> `remote_host` varchar(45) 
->); 

PHP部分：

$ipaddress = $_SERVER['REMOTE_ADDR']; 
$job_id  = $_GET['id']; 
/* 
* Checking if an entry exists for this JOB ID with this REMOTE HOST 
*/ 
$query = "SELECT id FROM pageviews WHERE ". 
         "job_id=".$job_id." AND remote_host='".$ipaddress."'"; 
$result = mysqli_query($dbc, $query); 
if(mysqli_num_rows($result) !== 1){ 
/* 
* There is no entry for this job_id. 
* So create an entry 
*/ 
    $query = "INSERT INTO pageviews (job_id,remote_host) VALUES ". 
     "(".$job_id.",'".$ipaddress."')"; 
    $result = mysqli_query($dbc, $query); 
    if($result){} 
    else{ 
    echo 'There was a problem inserting the data'; 
    exit(); 
    } 
} 

如果上面的PHP部分插入您的job.details.php，它會尋找在客戶端的IP地址，他/她正在訪問的JOB ID，然後在表格中插入一個條目，如果他/她正在訪問表格條目中不存在的IP的JOB ID。現在

，你可以得到「的次數作業ID：$ _GET [」身份證「]被視爲」使用簡單的查詢：

$query = "select id from pageviews where job_id=".$job_id.""; 
$result = mysqli_query($dbc, $query); 
echo "Number of times jobID: ".$job_id." was viewed = ".mysqli_num_rows($result); 

注：客戶端IP地址可以是代理服務器之後，或該IP可以是來自代理之後LAN的內部IP。所以不能真正相信$ _SERVER ['REMOTE_ADDR']提供的值。

您可以自由優化任何查詢，清理輸入內容，以不同方式創建表格。這只是實現你基本尋找的簡單方法之一。