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這是一個Spring應用程序,我試圖做一個POST請求並獲取響應。如何從POST請求獲取響應對象?
在服務器端我有這個
@CrossOrigin
@RequestMapping(value = "/test", method = RequestMethod.POST)
public
@ResponseBody
Test testmethod(@RequestBody Test test) {
test.setValue("test");
return test;
}
在客戶端我有POST方法應該返回測試對象。我使用JSON進行編碼。
public Object post(String url1, Test test) throws IOException, ClassNotFoundException {
ObjectMapper mapper = new ObjectMapper();
String jsonInString = mapper.writeValueAsString(login);
try {
DefaultHttpClient httpClient = new DefaultHttpClient();
HttpPost postRequest = new HttpPost(url1);
StringEntity input = new StringEntity(jsonInString);
input.setContentType("application/json");
postRequest.setEntity(input);
HttpResponse response = httpClient.execute(postRequest);
//read the object from the response, how to do that?
//responseObject = ?????
httpClient.getConnectionManager().shutdown();
} catch (MalformedURLException e) {
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
}
return responseObject;
}
而且
Test s = new Test;
Test s=(Test)post("http://localhost:8081/basic-web-app/test",s);
我的問題是,我不知道燙得到響應測試對象。請幫忙。謝謝!
但我並不需要一個字符串,需要一個測試對象。 – mlhack
你發送json,所以它是一個字符串。只需使用一些JSON到Object轉換器 – mariusz2108