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我有這些模型;有一個自定義管理器。如何在自定義模型管理器中使用帶註釋()的order_by
class OrderByHighestScoreManager(models.Manager):
def get_query_set(self, *args, **kwargs):
qs = super(OrderByHighestScoreManager, self).get_query_set(*args, **kwargs)
return qs.annotate(score=Count('votes'),).order_by('score')
class AbstractEntry(models.Model):
user = models.ForeignKey(User, null=True, blank=True)
last_modified = models.DateTimeField(auto_now=True)
objects = models.Manager()
order_by_votes = OrderByHighestScoreManager()
class Entry(AbstractEntry):
creation_date = models.DateTimeField(auto_now_add=True)
votes = generic.GenericRelation(Vote)
我不能讓自定義管理工作.... 這是OK:
Entry.objects.annotate(score=Count('votes__id'),).order_by('score')
這不起作用:
Entry.order_by_votes.all()
我得到的錯誤是:
Traceback (most recent call last):
File "c:\Python27\Lib\unittest\case.py", line 318, in run testMethod()
File "C:\Data\Development\django_projects\oko\________\apps\entries\tests\model.py",line 111, in test_order_by_votes
self.assertEqual(list(Entry.order_by_votes.values_list('id', flat=True)), [self.e1.id, self.e2.id])
File "C:\Data\Development\django_projects\oko\lib\site-packages\django\db\models\query.py", line 84, in __len__
self._result_cache.extend(self._iter)
File "C:\Data\Development\django_projects\oko\lib\site-packages\django\db\models\query.py", line 956, in iterator
for row in self.query.get_compiler(self.db).results_iter():
File "C:\Data\Development\django_projects\oko\lib\site-packages \django\db\models\sql\compiler.py", line 680, in results_iter
for rows in self.execute_sql(MULTI):
File "C:\Data\Development\django_projects\oko\lib\site-packages\django\db\models\sql\compiler.py", line 725, in execute_sql
sql, params = self.as_sql()
File "C:\Data\Development\django_projects\oko\lib\site-packages\django\db\models\sql\compiler.py", line 60, in as_sql
ordering, ordering_group_by = self.get_ordering()
File "C:\Data\Development\django_projects\oko\lib\site-packages\django\db\models\sql\compiler.py", line 349, in get_ordering
self.query.model._meta, default_order=asc):
File "C:\Data\Development\django_projects\oko\lib\site-packages\django\db\models\sql\compiler.py", line 378, in find_ordering_name
opts, alias, False)
File "C:\Data\Development\django_projects\oko\lib\site-packages \django\db\models\sql\query.py", line 1238, in setup_joins
"Choices are: %s" % (name, ", ".join(names)))
FieldError: Cannot resolve keyword 'score' into field. Choices are:
creation_date, id, last_modified, user, votes
什麼是goi這裏錯了嗎?
我非常想通過一個管理器或至少一個可從Entry實例中訪問的方法進行排序,因爲幾個模板將使用此特殊排序(並且我不想複製這個複雜的查詢集不同的看法)。
只是告訴人們我的進度:我發現將'order_by()'離開自定義管理器,並將其添加到我的視圖中的查詢集可以解決問題。儘管如此,它仍令我困惑。 – LaundroMat