如果數據在模態中,如果要將詳細信息插入到mysql數據庫中,我想請求一些幫助。我一直在努力完成這個我的樣本項目,希望我可以在未來使用它作爲一個投資組合。這是模態代碼。在模態中插入查詢
main.php
<div class="modal fade" id="registrationModalold" role="dialog">
<div class="modal-dialog">
<!-- Modal content-->
<div class="modal-content">
<!--<form action="functions/actions.php" method="POST">-->
<div class="modal-header">
<button type="button" class="close" data-dismiss="modal">×</button>
<h4 class="modal-title">Enrollment Details</h4>
</div>
<div class="modal-body">
<form method="post" action="functions/actions.php">
<h4 class="modal-title">Personal Information</h4>
<div class="row">
<div class="col-lg-6 col-xs-6">
<label for="usr">Name:</label>
<select class="form-control" name="courses">
<?php
include 'ini/db.php'; //connect to database
$sql = "SELECT distinct student_name FROM tbl_students";
$res = mysqli_query($conn,$sql);
echo "<option>---SELECT STUDENT---</option>";
while ($row = mysqli_fetch_array($res)){
echo "<option value=Course".$row['student_name'].">" . $row['student_name'] . "</option>";
}
?>
</select>
</div><!-- ./col -->
<div class="col-lg-6 col-xs-6">
<label for="usr">Addres:</label>
<input type="text" class="form-control" id="fullname">
</div><!-- ./col -->
</div>
<div class="row">
<div class="col-lg-3 col-xs-6">
<label for="usr">Contact:</label>
<input type="text" class="form-control" id="fullname">
</div><!-- ./col -->
<div class="col-lg-3 col-xs-6">
<label for="usr">BirthDate:</label>
<input type="text" class="form-control" id="fullname">
</div><!-- ./col -->
<div class="col-lg-3 col-xs-6">
<label for="usr">Birth Place:</label>
<input type="text" class="form-control" id="fullname">
</div><!-- ./col -->
<div class="col-lg-3 col-xs-6">
<label for="usr">Gender:</label>
<select class="form-control">
<option id="male">Male</option>
<option id="female">Female</option>
</select>
</div><!-- ./col -->
</div>
</br></br>
<h4 class="modal-title">Other Information</h4>
<div class="row">
<div class="col-lg-6 col-xs-6">
<label for="usr">Course:</label>
<select class="form-control" name="courses">
<?php
include 'ini/db.php'; //connect to database
$sql = "SELECT crs_id,crs_name FROM tbl_courses";
$res = mysqli_query($conn,$sql);
echo "<option>---SELECT COURSE---</option>";
while ($row = mysqli_fetch_array($res)){
echo "<option value=Course".$row['crs_id'].">" . $row['crs_name'] . "</option>";
}
?>
</select>
</div><!-- ./col -->
<div class="col-lg-6 col-xs-6">
<label for="usr">Major: <font color="red" size="2"><i>optional</i></font></label>
<input type="text" class="form-control" id="fullname">
</div><!-- ./col -->
</div>
<div class="row">
<div class="col-lg-3 col-xs-6">
<label for="usr">Mother's Name:</label>
<input type="text" class="form-control" id="fullname">
</div><!-- ./col -->
<div class="col-lg-3 col-xs-6">
<label for="usr">Mother's Occupation:</label>
<input type="text" class="form-control" id="fullname">
</div><!-- ./col -->
<div class="col-lg-3 col-xs-6">
<label for="usr">Father's Name:</label>
<input type="text" class="form-control" id="fullname">
</div><!-- ./col -->
<div class="col-lg-3 col-xs-6">
<label for="usr">Father's Occupation:</label>
<input type="text" class="form-control" id="fullname">
</div><!-- ./col -->
</div>
</div>
<div class="modal-footer">
<button name="btnregister" action="functions/actions.php" type="button" class="btn btn-default">Save</button>
<button type="button" class="btn btn-default" data-dismiss="modal">Close</button>
</div>
</form>
</div>
</div>
</div>
</div>
正如你可以看到有有一個按鈕,它指向我的actions.php這是另一個文件夾是功能文件夾內的按鈕。但是,當我點擊沒有任何反應。
這裏的action.php
:
if (isset($_POST['btnregisters'])) {
echo "ASASASASASASASASASASAS";
die("asdsadsada");
}
'<標籤=「USR」>父親名稱:' - 輸入的「id」需要匹配與其關聯的標籤的'for'屬性。 – Quentin