找到了解決問題的方法,也許這對某人來說是有幫助的。 我沒有包含任何檢查,這是更多的測試用例,看看是否有用。
public class TestReadMultiDimensionArray {
private int[] startPosition; //Start position.
private int[] endPosition; //End position.
private boolean inRange = false; //If the current position is in range.
private List<Object> result; //List to store the values we find.
public TestReadMultiDimensionArray() {
result = new ArrayList<>();
}
public static void main(String[] args) {
TestReadMultiDimensionArray test = new TestReadMultiDimensionArray();
Integer[][][][] testSubject = new Integer[2][2][4][];
//(0,0,y,z)
testSubject[0][0][0] = new Integer[]{1}; //(0,0,0,0)
testSubject[0][0][1] = new Integer[]{2}; //(0,0,1,0)
testSubject[0][0][2] = new Integer[]{3}; //(0,0,2,0)
testSubject[0][0][3] = new Integer[]{4}; //(0,0,3,0)
//(0,1,y,z)
testSubject[0][1][0] = new Integer[]{5}; //(0,1,0,0)
testSubject[0][1][1] = new Integer[]{6}; //(0,1,1,0)
testSubject[0][1][2] = new Integer[]{7, 8, 9}; //(0,1,2,0) (0,1,2,1) (0,1,2,2)
testSubject[0][1][3] = new Integer[]{10}; //(0,1,3,0)
//(1,0,y,z)
testSubject[1][0][0] = new Integer[]{11, 12}; //(1,0,0,0)..
testSubject[1][0][1] = new Integer[]{13, 14, 15};
testSubject[1][0][2] = new Integer[]{16, 17, 18};
testSubject[1][0][3] = new Integer[]{19, 20, 21}; //..(1,0,3,2)
//(1,1,y,z)
testSubject[1][1][0] = new Integer[]{22, 23}; //(1,1,0,0)..
testSubject[1][1][1] = new Integer[]{24, 25, 26};
testSubject[1][1][2] = new Integer[]{27, 28, 29, 30, 31, 32, 33, 34};
testSubject[1][1][3] = new Integer[]{35, 36}; //..(1,1,3,1)
//Launch the test.
test.readValue(testSubject);
}
/**
*
* @param obj The Array from where we want to get the data.
*/
public void readValue(Object obj) {
//Where should it start.
startPosition = new int[]{0, 1, 0, 0};
//Where should it stop.
endPosition = new int[]{1, 1, 1, 2};
System.out.println("Start Position:" + Arrays.toString(startPosition) + " End Position:" + Arrays.toString(endPosition));
int[] currentPosition = new int[]{-1, -1, -1, -1};
//Call to the method.
testRead((Object[]) obj, 0, currentPosition);
//Result to array.
Object[] arrayToReturn = result.toArray(new Object[0]);
System.out.println("Result: " + Arrays.toString(arrayToReturn));
}
/**
* Recursive method that looks for the values in a multi-dimensional array, in a given range. /!\ No checks are implemented here, wrong input can end in a
* StackOverFlow.
*
* @param obj The array in Object[] form.
* @param currentDimension The dimension we are currently in.
* @param result The reference to the list that will store all the values we found.
* @param currentPosition The current position we are in.
*/
private void testRead(Object[] obj, int currentDimension, int[] currentPosition) {
for (int i = 0; i < obj.length; i++) {
currentPosition[currentDimension] = i;
if (Arrays.equals(startPosition, currentPosition) && currentDimension == (currentPosition.length - 1)) {
//Found the start position.
System.out.println("############ START ############");
inRange = true;
}
if ((i >= startPosition[currentDimension] && i <= endPosition[currentDimension]) || inRange == true) {
//We are in the write track to get to the values we are looking for.
if (obj[i] instanceof Object[]) {
//The data contained in the cell is an array.
testRead((Object[]) obj[i], currentDimension + 1, currentPosition);
} else {
//The data contained in the cell is a scalar. This is what we where looking for.
System.out.println(Arrays.toString(currentPosition) + " Data: " + obj[i]);
result.add(obj[i]);
}
}
if (Arrays.equals(endPosition, currentPosition) && currentDimension == (currentPosition.length - 1)) {
//Found the end position.
System.out.println("############ END ############");
inRange = false;
}
}
}
}
任何問題或想法,以更好的代碼是值得歡迎的。
這可能不是建議的方法,原因很多。我能問你想要完成什麼嗎?我可能會重新考慮你在解決問題的方式。 – Kurtymckurt
對於服務器來說,其中一項服務是從任何維數的數組中讀取一系列值。數組沒有預定義,並且沒有角度限制(我寫了255,因爲來自Java的維度上限)。這是在服務器啓動時創建的,並來自配置文件。順便說一下,歡迎任何替代方式或想法,謝謝。 – gabun88
您可以將數據中的維數作爲參數傳入嗎?如果調用代碼知道它(至少對於這種用法),編寫一個算法來解決這個問題毫無意義。 – Kurtymckurt