MySQL查詢登錄

Question

我創建一個簡單的登錄信息（用戶，密碼和功率水平; 1 - 普通用戶2，管理員）

所以，我的表只能有4列（ID，用戶名，密碼和lvl）。我已經有查詢輸入登錄，我想要的是創建一個「if」/條件來打開一個表單。例如，如果您輸入了您的信息，並且您是「Normal_user」表單顯示的普通用戶，但是如果您是管理員，則表單「Admin」會顯示。我的實際代碼沒有經過許可的級別是：

try 
     { 
      MySqlConnection c = new MySqlConnection("Server=localhost; database=SOIS; UID=root; Pwd=; "); 
      MySqlCommand cmd = new MySqlCommand("Select * from usuarios where empleado_id = '" + username.Text + "' and password = '" + password.Password + "'", c); 
       MySqlDataReader lectura; 
       c.Open(); 
       lectura = cmd.ExecuteReader(); 
       int count = 0; 
       while (lectura.Read()) { 
        count = count + 1; 
       } 
       if (count == 1) 
       { 
        MainWindow win2 = new MainWindow(); 
        win2.Show(); 
        c.Close();  //In this part I think can add another query and put it into an if 
        this.Close(); 
       } 
       else 
       { 
        c.Close(); 
       MessageBox.Show("Wrong information"); 
      } 

      c.Close(); 
     }catch(Exception ex) 
     { 
      MessageBox.Show(ex.ToString()); 
     } 

Answer 1

我假設您在數據庫中有第4列來標識管理用戶。

try 
     { 
      MySqlConnection c = new MySqlConnection("Server=localhost; database=SOIS; UID=root; Pwd=; "); 
      MySqlCommand cmd = new MySqlCommand("Select * from usuarios where empleado_id = '" + username.Text + "' and password = '" + password.Password + "'", c); 
       MySqlDataReader lectura; 
       c.Open(); 
       lectura = cmd.ExecuteReader(); 
       int count = 0; 
       bool isAdmin = false; 
       while (lectura.Read()) { 
        count = count + 1; 
        isAdmin = (lecture[3] == 1) ? true : false; 
       } 
       if (count == 1) 
       { 
        MainWindow win2 = new MainWindow(); 
        win2.Show(); 
        if(isAdmin) { 
         // if admin open admin form 
        } 
        c.Close();  //In this part I think can add another query and put it into an if 
        this.Close(); 
       } 
       else 
       { 
        c.Close(); 
       MessageBox.Show("Wrong information"); 
      } 

      c.Close(); 
     }catch(Exception ex) 
     { 
      MessageBox.Show(ex.ToString()); 
     }