這兩個數組之間有什麼區別，爲什麼typeahead w/autoform只能和其中的一個一起工作？

Question

這裏是我的SimpleSchema：

confirmedAddress: { 
    //addressRecordID 
    type: String, 
    label: "Address", 
    optional: true, 
    autoform: { 
     type: "typeahead", 
     /* 
     options: function() { 
      return [{ 
       label: "2013", 
       value: 2013 
      }, { 
       label: "2014", 
       value: 2014 
      }, { 
       label: "2015", 
       value: 2015 
      }] 
     } 
     */ 
     options: function() { 
      var addresses = Addresses.find({ 
       houseNumber: "0" 
      }).map(function(address) { 
       return { 
        label: address.houseNumber + " " + address.street + ", " + address.unit + ", " + address.city, 
        value: address._id 
       }; 
      }); 
      /*console.log("addresses",addresses)*/ 
      var addresses2 = [{ 
       "label": "0 Unknown, undefined, undefined", 
       "value": "rec2I5yyHm6rSQOAO" 
      }, { 
       "label": "0 unknown, undefined, undefined", 
       "value": "recBEYzyvjfCm0D4k" 
      }, { 
       "label": "0 Unknown, undefined, undefined", 
       "value": "recFdDsCzYgXGWWyC" 
      }, { 
       "label": "0 SE Muskogee Ave, undefined, undefined", 
       "value": "recH0g6UvLrztSCCR" 
      }, { 
       "label": "0 Unknown, undefined, undefined", 
       "value": "recK8aT6gQoRsqDVP" 
      }, { 
       "label": "0 unknown, undefined, undefined", 
       "value": "recKstPZAt5wrGzRT" 
      }, { 
       "label": "0 Unknown, undefined, undefined", 
       "value": "recSf7X7LLIWqvvGK" 
      }, { 
       "label": "0 Unknown, undefined, undefined", 
       "value": "recbUExSc2Rd1kFSp" 
      }, { 
       "label": "0 Oak, undefined, undefined", 
       "value": "recekb3FlD6vghcf0" 
      }, { 
       "label": "0 Unknown, undefined, undefined", 
       "value": "rechiCWJ9ScAeBOC4" 
      }, { 
       "label": "0 Unknown, undefined, undefined", 
       "value": "reclUGe2NkeLSafWj" 
      }, { 
       "label": "0 unknown, undefined, undefined", 
       "value": "reclsD03UdhBwLc6b" 
      }, { 
       "label": "0 Moved out of territory, undefined, undefined", 
       "value": "recrLqh76Qk7EHQcm" 
      }, { 
       "label": "0 Unknown, undefined, undefined", 
       "value": "recyyDLXMkHMRf9bn" 
      }] 
      console.log(addresses, addresses2) 
      console.log("addresses == addresses2", addresses == addresses2) // false 
      return addresses2 
     } 
    } 
} 

第一註釋部分工作正常。返回addresses2也可以正常工作。但是，當我返回addresses時，typeahead不起作用。

的事情是，我通過這個粘貼到控制檯，然後複製成代碼得到addresses2：

Addresses.find({ 
    houseNumber: "0" 
}).map(function(address) { 
    return { 
     label: address.houseNumber + " " + address.street + ", " + address.unit + ", " + address.city, 
     value: address._id 
    }; 
}); 

缺少什麼我在這裏？

Answer 1

問題是，當創建html表單時，addresses是一個空數組，因爲它正在創建。 addresses2是硬編碼的，因此可立即使用。