Mysql的獲得最小值，平均值和最新的兩個表（產品，在產品，價格）

Question

我有兩個MySQL表：

• products與ID，姓名，聯繫
• products-prices與ID，id_prod，價格，可用性和日期

在第二個，你可以看到我可以有更多的價格爲相同的產品取決於更新的時間，我想要做的是有一個查詢，告訴我最低價格，平均價格和最新價格。我可以在一個查詢中獲得前兩個（最低和平均價格），在另一個查詢中獲得最新價格，但我不知道如何連接它們或者是否有其他方式。

我的第一個查詢看起來像這樣：

SELECT 
    `products`.id AS ids, `products`.name, `products`.link, 
    `products-prices`.id AS id_p, `products-prices`.price, 
    `products-prices`.availability, `products-prices`.date, 
    AVG(`products-prices`.price) AS medie, 
    MIN(`products-prices`.price) AS minim 
FROM 
    `products-prices` 
INNER JOIN 
    `products` ON `products`.id = `products-prices`.id_produs 
GROUP BY 
    ids 
ORDER BY 
    ids 

，第二個是：

SELECT * 
FROM `products-prices` 
WHERE date IN (SELECT DISTINCT MAX(date) max_date 
       FROM `products-prices` 
       GROUP BY id_produs) 

你能給我一個想法，如何將它們結合起來？非常感謝你！

（我不知道如何工會的工作，如果它的作品，我會嘗試）

//編輯：我也有一個問題，我可以得到MIN，AVG值，而最新的入門在數據庫中？

Answer 1

這是一個未經考驗的解決方案，請讓我知道它是否有助於

SELECT 
    `products`.id AS ids, `products`.name, `products`.link, 
    `products-prices`.id AS id_p, `products-prices`.price, 
    `products-prices`.availability, `products-prices`.date, 
    AVG(`products-prices`.price) AS medie, 
    MIN(`products-prices`.price) AS minim, 
    latest.`date` as latest_date, 
    latest.price as latest_price 
FROM 
    `products-prices` 
INNER JOIN 
    `products` ON `products`.id = `products-prices`.id_produs 
INNER JOIN 
    (select id_produs, price, `date` 
    from `products-prices` t1 
    where not exists (select 1 
         from `products-prices` t2 
         where t1.`date` < t2.`date` and t1.id_produs = t2.id_produs) 
    group by id_produs 
    ) latest  
ON 
    latest.id_produs = products.id 
GROUP BY 
    ids 
ORDER BY 
    ids 

Answer 2

你可以使用子查詢的最大日期

select 
     `products`.id AS ids, 
     `products`.name, 
     `products`.link, 
     t.date, 
     t.price, 
     t.availability, 
     AVG(`products-prices`.price) AS medie, 
     MIN(`products-prices`.price) AS minim 

    from `products` 
    inner join `products-prices` ON `products`.id=`products-prices`.id_produs 
    inner join () 
    select id_produs, date, price, availability 
    from `products-prices` 
    where (id_produs, date) = (
    select id_produs, max(date) as max_date 
    from `products-prices` 
    group by id) t on t.id_produs = `products`.id_prod