採用了棱角分明怎樣才能撥打電話完成一堆異步調用

Question

後，這是我在控制器代碼

myFactory.getPoints().success(function (data) { 
    $scope.points = data; 
}); 

myFactory.getStates().success(function (data) { 
    $scope.states = data; 
}); 

myFactory.getLeases().success(function (data) { 
    $scope.leases = data; 
}); 

我期待$ scope.leases後$ scope.points和$ scope.states得到值獲得他們的價值。我知道$ q與.then不同步。是對的嗎？

答：我從答案推導如下

$q.all([ 
     myFactory.getPoints().success(function (data) { 
      $scope.Points = data; 
     }).error(function (data) { 
      $scope.error = "An Error has occurred while loading Points! " + data.ExceptionMessage; 
     }), //more, more, more 

    ]).then(function() { 
     myFactory.getLease().success(function (data) { 
      $scope.leases = data; 
     }).error(function (data) { 
      $scope.error = "An Error has occurred while loading Leases! " + data.ExceptionMessage; 
     }) 
}); 

Answer 1

問題是成功（）不返回原始承諾。 then()調用返回一個承諾（使用從回調函數返回的值解析），而.success()是更傳統的註冊回調方式，並且不返回承諾。

所以，妥善的解決辦法是

$q.all([ 
    myFactory.getPoints().then(function (response) { 
     $scope.points = response.data; 
     return response.data; 
    }), 

    myFactory.getStates().then(function (response) { 
     $scope.states = response.data; 
     return response.data; 
    }), 

    myFactory.getLeases().then(function (response) { 
     $scope.leases = response.data; 
     return response.data; 
    }) 
]).then(function(responses) { 
    // xxx 
}); 

Answer 2

您可以鏈的承諾一起，以讓他們同步執行：

myFactory.getPoints().success(function (data) { 
    $scope.points = data; 

    return myFactory.getStates(); 
}) 
.success(function (data) { 
    $scope.states = data; 

    return myFactory.getLeases(); 
}) 
.success(function (data) { 
    $scope.leases = data; 
});