如何正確訪問和遍歷Ruby中的多維數組？

Question

我的代碼塊：

super_heroes = [ 
    ["Spider Man", "Peter Parker"], 
    ["Deadpool", "Wade Wilson"], 
    ["Wolverine", "James Howlett"] 
] 

super_heroes.each do |sh| 
    sh.each do |heroname, realname| 
     puts "#{realname} is #{heroname}" 
    end 
end 

輸出是這樣的：

is Spider Man 
is Peter Parker 
is Deadpool 
is Wade Wilson 
is Wolverine 
is James Howlett 

，但我想是這樣的：

Peter Parker is Spider Man 
Deadpool is Wade Wilson 
Wolverine is James Howlett 

後迭代代碼的時間，我仍然無法弄清楚。如果有人能把我放在正確的方向並解釋我做錯了什麼，我將不勝感激。謝謝！

Answer 1

如下活動：

super_heroes = [ 
    ["Spider Man", "Peter Parker"], 
    ["Deadpool", "Wade Wilson"], 
    ["Wolverine", "James Howlett"] 
] 

super_heroes.each do |heroname, realname| 
    puts "#{realname} is #{heroname}" 
end 

# >> Peter Parker is Spider Man 
# >> Wade Wilson is Deadpool 
# >> James Howlett is Wolverine 

什麼與您的代碼發生了什麼？

super_heroes.each do |sh| # sh is ["Spider Man", "Peter Parker"] etc.. 
    # here **heroname** is "Spider Man", "Peter Parker" etc. 
    # every ietration with sh.each { .. } your another variable **realname** 
    # is **nil** 
    sh.each do |heroname, realname| 
     puts "#{realname} is #{heroname}" 
     # as **realname** is always **nil**, you got the output as 
     # is Spider Man 
     # is Peter Parker 
     # ..... 
     # ..... 
    end 
end 

Answer 2

試試這個也

super_heroes.each do |sh| 
    puts sh.join(" is ") 
end