在後續插入中使用插入的ID

Question

如何獲取在用戶表中創建的seeker_ID並將其添加到文檔表中？可能嗎？

這是到目前爲止我的代碼：

$link = mysqli_connect("localhost", "user", "password", "database"); 

$query = "INSERT INTO users (first_name, last_name) VALUES ('$FirstName','$LastName')"; 
$query = "INSERT INTO documents (seeker_ID, filename) VALUES ('','$filename')"; 

if (mysqli_multi_query($link, $query)) { 
    echo "Candidate ID: $seeker_id <br>"; 
    echo "Candidate First Name: $FirstName <br>"; 
    echo "Candidate Last Name: $LastName<br>"; 
    echo "Email: $Email <br>"; 
    echo "<br><br>Records added successfully - Refreshing In 5 Seconds<br>"; 
} else { 
    echo "ERROR: Could not able to execute $sql. " . mysqli_error($link); 
} 
// close connection 
mysqli_close($link); 

Answer 1

這是不是真的有幫助。首先我要假設這是MySQL。如果是這樣，我建議使用PDO。

如果包含表單數據的請求是HTTP GET或POST，你可以做以下之一：

$seeker_ID = htmlentities($_GET["seeker_ID"]); 

然後你就可以使用該變量來構建查詢。但請使用PDO：

$pdo = new PDO("mysql:host=$dbhost;dbname=$dbname", $dbusername, $dbpass); 

$stmt = $pdo->prepare("INSERT INTO documents(seeker_ID, filename) VALUES (:seeker_ID, :filename)"); 
$stmt->execute([ 
    "filename" => $filename, 
    "seeker_ID" => $seeker_ID 
]);