Python通過值（一個列表）排序兩個通訊錄列表

Question

有兩個對應的1對1關係列表。

names = ["David", "Peter", "Kate", "Lucy", "Kit", "Jason", "Judy"] 
scores = [1,1,0.8,0.2,0.4,0.1,0.6] 

我想告訴誰在1線場得分超過0.5，顯示：

Peter (1 point), David (1 point), Kate (0.8 point), Judy (0.6 point) 

我想的是：

import operator 

names = ["David", "Peter", "Kate", "Lucy", "Kit", "Jason", "Judy"] 
scores = [1,1,0.8,0.2,0.4,0.1,0.6] 

dictionary = dict(zip(names, scores)) 

dict_sorted = sorted(dictionary.items(), key=operator.itemgetter(1), reverse=True) 

print dict_sorted 

它提供：

[('Peter', 1), ('David', 1), ('Kate', 0.8), ('Judy', 0.6), ('Kit', 0.4), ('Lucy', 0.2), ('Jason', 0.1)] 

它如何才能進一步得到結果想？注意：需要從大到小的排序結果。

2再爲測試目的列表：

names = ["Olivia","Charlotte","Khaleesi","Cora","Isla","Isabella","Aurora","Amelia","Amara","Penelope","Audrey","Rose","Imogen","Alice","Evelyn","Ava","Irma","Ophelia","Violet"] 
scores = [1.0, 1.0, 0.8, 0.2, 0.2, 0.4, 0.2, 0.0, 1.0, 0.2, 0.4, 0.2, 1.0, 0.0, 0.8, 0.0, 1.0, 0.0, 0.6] 

Answer 1

這應該做的伎倆：

names = ["David", "Peter", "Kate", "Lucy", "Kit", "Jason", "Judy", "Mark", "John", "Irene"] 
scores = [1,1,0.8,0.2,0.4,0.1,0.6,0.7,0.3,1.2] 

print(', '.join('{} ({} points)'.format(name, points) for name, points in sorted(zip(names, scores), key=__import__('operator').itemgetter(1), reverse=True) if points > 0.5)) 

輸出：

Irene (1.2 points), David (1 points), Peter (1 points), Kate (0.8 points), Mark (0.7 points), Judy (0.6 points) 

Answer 2

你也使用OrderedDict形式collections模塊，如果你想要排序的輸出。

from collections import OrderedDict 

names = ["David", "Peter", "Kate", "Lucy", "Kit", "Jason", "Judy"] 
scores = [1,1,0.8,0.2,0.4,0.1,0.6] 

dict_sorted = OrderedDict((k, v) for k, v in zip(names, scores) if v > 0.5) 
print(', '.join('{} ({} points)'.format(k, v) for k, v in dict_sorted.items())) 

打印： David (1 points), Peter (1 points), Kate (0.8 points), Judy (0.6 points)

Answer 3

爲此，您可以在同一行，但它容易得多，如果你分階段做閱讀。首先選擇分數大於閾值的項目，然後對它們進行排序。

import operator 

names = ["Olivia","Charlotte","Khaleesi","Cora","Isla","Isabella","Aurora","Amelia","Amara","Penelope","Audrey","Rose","Imogen","Alice","Evelyn","Ava","Irma","Ophelia","Violet"] 
scores = [1.0, 1.0, 0.8, 0.2, 0.2, 0.4, 0.2, 0.0, 1.0, 0.2, 0.4, 0.2, 1.0, 0.0, 0.8, 0.0, 1.0, 0.0, 0.6] 

threshold = 0.5 
lst = [(name, score) for name, score in zip(names, scores) if score > threshold] 
lst.sort(reverse=True, key=operator.itemgetter(1)) 
print(lst) 

輸出

[('Olivia', 1.0), ('Charlotte', 1.0), ('Amara', 1.0), ('Imogen', 1.0), ('Irma', 1.0), ('Khaleesi', 0.8), ('Evelyn', 0.8), ('Violet', 0.6)] 

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下面是一行代碼版本：

print(sorted(((name, score) for name, score in zip(names, scores) if score > 0.5), reverse=True, key=operator.itemgetter(1)))