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爲什麼此代碼的工作（只要它拉回到一個空的「CustomerObject」在Chrome控制檯爲什麼查詢只在一個函數中不包含返回數據
var CustomerObject = Parse.Object.extend("CustomerObject");
var retrieve = new Parse.Query(CustomerObject);
retrieve.equalTo("customernumber", $('#searchnumber').val());
retrieve.first({
success: function(retrieveResults)
{
}
});
var cname = retrieve.get("customername");
var cnumber = retrieve.get("customernumber");
查看，但該代碼內當用戶點擊搜索按鈕功能不返回任何 「CustomerObject」？
HTML
<input type="text" name="searchnumber" id="searchnumber" value="" placeholder="Customer Number"/>
<button type="submit" onclick = "search" >Find</button>
JS
function search() {
var CustomerObject = Parse.Object.extend("CustomerObject");
var retrieve = new Parse.Query(CustomerObject);
retrieve.equalTo("customernumber", $('#searchnumber').val());
retrieve.first({
success: function(retrieveResults)
{
}
});
var cname = retrieve.get("customername");
var cnumber = retrieve.get("customernumber");
};