我在http://www.w3schools.com/php/php_ajax_database.asp處發現了以下腳本。但我發現很難通過wordpress實現,這在本地主機完美工作,但在wordpress失敗。我已經完成搜索w /相同的過程,但仍然無法弄清楚。我可以一步一步詢問如何通過wordpress調用ajax腳本嗎?wordpress ajax - 通過wordpress通過AJAX從數據庫獲取信息
**的我的自定義的FrontPage * *
<?php
/*
Template Name: Custom Template
*/
?>
<?php
/**
* The template for displaying all pages.
*
* This is the template that displays all pages by default.
* Please note that this is the WordPress construct of pages
* and that other 'pages' on your WordPress site will use a
* different template.
*
* @package WordPress
* @subpackage Twenty_Eleven
* @since Twenty Eleven 1.0
*/
get_header(); ?>
<script>
function showUser(str)
{
if (str=="")
{
document.getElementById("txtHint").innerHTML="";
return;
}
if (window.XMLHttpRequest)
{// code for IE7+, Firefox, Chrome, Opera, Safari
xmlhttp=new XMLHttpRequest();
}
else
{// code for IE6, IE5
xmlhttp=new ActiveXObject("Microsoft.XMLHTTP");
}
xmlhttp.onreadystatechange=function()
{
if (xmlhttp.readyState==4 && xmlhttp.status==200)
{
document.getElementById("txtHint").innerHTML=xmlhttp.responseText;
}
}
xmlhttp.open("GET","getuser.php?q="+str,true);
xmlhttp.send();
}
</script>
<div id="primary">
<div id="content" role="main">
<form>
<select name = "users" onChange = "showUser(this.value)">
<?php
include 'dbconfig.php';
$result=mysql_query("SELECT DISTINCT lastname FROM people ORDER BY lastname ASC;");
echo '<option value="">' . 'Select an Agent' . '</option>';
while ($row=mysql_fetch_array($result))
{
echo '<option value="' . $row['lastname'] . '">' . $row['lastname'] . '</option>';
}
?>
</select>
</form>
<br>
<div id="txtHint"><b>Person info will be listed here.</b></div>
</div><!-- #content -->
</div><!-- #primary -->
<?php get_footer(); ?>
PHP文件(getuser.php)
<?php
$q = intval($_GET['q']);
include 'dbconfig.php'; // PHP File to login credentials
$sql="SELECT * FROM people WHERE id = '".$q."'";
$result = mysql_query($sql);
echo "<table border='1'>
<tr>
<th>Firstname</th>
<th>Lastname</th>
<th>Age</th>
<th>Hometown</th>
<th>Job</th>
</tr>";
while($row = mysql_fetch_array($result))
{
echo "<tr>";
echo "<td>" . $row['FirstName'] . "</td>";
echo "<td>" . $row['LastName'] . "</td>";
echo "<td>" . $row['Age'] . "</td>";
echo "<td>" . $row['Hometown'] . "</td>";
echo "<td>" . $row['Job'] . "</td>";
echo "</tr>";
}
echo "</table>";
mysql_close($con);
?>
<?php
$q = intval($_GET['q']);
include 'dbconfig.php'; // PHP File to login credentials
$sql="SELECT * FROM people WHERE id = '".$q."'";
$result = mysql_query($sql);
echo "<table border='1'>
<tr>
<th>Firstname</th>
<th>Lastname</th>
<th>Age</th>
<th>Hometown</th>
<th>Job</th>
</tr>";
while($row = mysql_fetch_array($result))
{
echo "<tr>";
echo "<td>" . $row['firstname'] . "</td>";
echo "<td>" . $row['lastname'] . "</td>";
echo "<td>" . $row['age'] . "</td>";
echo "<td>" . $row['hometown'] . "</td>";
echo "<td>" . $row['job'] . "</td>";
echo "</tr>";
}
echo "</table>";
mysql_close($con);
?>
採取的行動: 轉換(的getUser。 PHP)作爲函數,然後添加到主題functions.php。然後打電話給wp add_action hook.please看下面
function getuser(){
//get the data from ajax() call
//copied script from getuser.php
}
// creating Ajax call for WordPress
add_action('wp_ajax_nopriv_getuser', 'getuser');
add_action('wp_ajax_getuser', 'getuser');
您的幫助非常感謝。謝謝。解決
[見這個答案](http://stackoverflow.com/questions/20831673/send-a-form-from-jquery-to-php-with-ajax-wordpress/20831780#20831780),它可能會有一些見解。 – Ohgodwhy