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我正在做一個關於使用向量的開放尋址散列表的項目。這個項目的一個方面是使用模板來允許用戶定義矢量的類型。我已經實現了模板,如果我在編譯之前創建了一個對象,它會起作用,但我無法弄清楚如何讓用戶在運行時決定類型。類模板,允許用戶定義C++類型
該程序是面向對象的,並且類型必須傳遞給構造函數。起初我認爲簡單,如果陳述會起作用,但是我從那以後知道這不起作用。任何人都可以幫我解決這個問題嗎?謝謝
#include <iostream>
#include <string>
#include <vector>
using namespace std;
template <class T>
class OpenHash
{
private:
vector <T> hashTab;
vector <int> emptyCheck;
int hashF(string);
public:
OpenHash(int);
int getVectorCap();
int addRecord (T);
int sizeHash();
int find(T);
int printHash();
int deleteEntry(T);
};
template <class T>
OpenHash<T>::OpenHash(int vecSize)
{
hashTab.clear();
hashTab.resize(vecSize);
emptyCheck.resize(vecSize);
for (int i=0; i < emptyCheck.capacity(); i++)
{
emptyCheck.at(i) = 0;
}
}
template <class T>
int OpenHash<T>::getVectorCap()
{
int cap = hashTab.capacity();
int capE = emptyCheck.capacity();
cout << cap << capE;
return 0;
}
template <class T>
int OpenHash<T>::hashF (string key)
{
int ascii = 0, hasVal = 0;
for (int i = 0; i < key.size(); i++)
{
ascii += key[i];
}
hasVal = ascii % hashTab.capacity();
return hasVal;
}
template <class T>
int OpenHash<T>::addRecord(T key)
{
if (sizeHash() == emptyCheck.size())
{
cout << "Your hash table is full cannot add any more records" << endl;
}
else
{
bool findPos = false;
for (int j=0; j<hashTab.capacity(); j++)
{
if (hashTab.at(j) == key)
{
cout << "Element ready exists in hashtable" << endl;
return 0;
}
}
int hashVal = hashF(key);
for (int i=hashVal; i<emptyCheck.capacity(); i++)
{
if (emptyCheck.at(i) == 0)
{
hashTab.at(i) = key;
emptyCheck.at(i) = 1;
cout << "Element added at" << '[' << i << ']' << endl;
findPos = true;
return 0;
}
else
{
cout << "Collision probing through..." << endl;
}
}
if (findPos == false)
{
for (int x=0; x<emptyCheck.capacity(); x++)
{
if (emptyCheck.at(x) == 0)
{
hashTab.at(x) = key;
emptyCheck.at(x) = 1;
cout << "Element added at" << '[' << x << ']' << endl;
findPos=true;
return 0;
}
}
cout << "Element could not be added" << endl;
}
}
return 1;
}
template <class T>
int OpenHash<T>::sizeHash()
{
int elementsFilled = 0;
for (int i = 0; i<emptyCheck.capacity(); i++)
{
if (emptyCheck.at(i) != 0)
{
elementsFilled++;
}
}
return elementsFilled;
}
template <class T>
int OpenHash<T>::find(T key)
{
int hashVal = hashF(key);
bool findLoop = false;
for (int i=hashVal; i < hashTab.capacity(); i++)
{
if (hashTab.at(i) == key && emptyCheck.at(i) == 1)
{
cout << "Element found at position: " << '[' << i << ']' << endl;
cout << key << endl;
findLoop = true;
return 0;
}
else
{
cout << "Element not found at position! Probing through..." << endl;
}
}
if (findLoop == false)
{
for (int j = 0; j < hashTab.capacity(); j++)
{
if (hashTab.at(j) == key && emptyCheck.at(j) != 0)
{
cout << "Element found at position: " << '[' << j << ']' << endl;
cout << key << endl;
findLoop = true;
return 0;
}
}
cout << "Entry not found" << endl;
}
return 1;
}
template <class T>
int OpenHash<T>::deleteEntry(T toDel)
{
int hashVal = hashF(toDel);
bool foundDel = false;
for (int i = hashVal; i<hashTab.capacity(); i++)
{
if (hashTab.at(i) == toDel)
{
emptyCheck.at(i) = 0;
foundDel = true;
cout << "Entry deleted!" << endl;
return 0;
}
}
if (foundDel == false)
{
for (int j=0; j<hashTab.capacity(); j++)
{
if (hashTab.at(j) == toDel)
{
emptyCheck.at(j) = 0;
foundDel = true;
cout << "Entry deleted!" << endl;
return 0;
}
}
cout << "The member to delete was not found" << endl;
}
return 1;
}
template <class T>
int OpenHash<T>::printHash()
{
if (sizeHash() == 0)
{
cout << "No elements filled to print!" << endl;
}
for (int i=0; i<emptyCheck.capacity(); i++)
{
if (emptyCheck.at(i) != 0)
{
cout << "Record at:" << '[' << i << ']' << hashTab.at(i) << endl;
}
}
return 0;
}
int main()
{
cout << "Please input the size of your HashTable" << endl;
int vecSize = 0;
cin >> vecSize;
OpenHash<string> newTable(vecSize);
bool menu = true;
char choice;
while (menu == true)
{
cout << "Welcome to the open address hash table program, please input your choice:" << endl;
cin >> choice;
if (choice == 'a')
{
cout << "Please type in the record you wish to add:" << endl;
string rec;
getline(cin, rec);
newTable.addRecord(rec);
}
if (choice == 's')
{
cout << "Number of elements filled: " << newTable.sizeHash() << endl;
}
if (choice == 'f')
{
cout << "Please enter the string you wish to find" << endl;
string key;
getline(cin, key)
newTable.find(key);
}
if (choice == 'p')
{
cout << "Printing table..." << endl;
newTable.printHash();
}
if (choice == 'd')
{
cout << "Please input the item you wish to delete:" << endl;
string toDel;
getline(cin, toDel)
newTable.deleteEntry(toDel);
}
if (choice == 'x')
{
cout << "Thankyou" << endl;
menu = false;
}
}
return 0;
}
類型不傳遞給構造函數; *參數*(當然,它們具有類型,但在語言意義上它們本身不是「類型」)。顯示您現有的代碼將比您告訴我們更多的清晰度。這聽起來像是你有一個可由用戶選擇的可配置類型庫,但這純粹是沒有任何支持的猜測。 – WhozCraig
請顯示代碼! –