我試圖抓住所有的ID所PART_NUMBER並在同一時間給他們1到我的Ajax調用:JQuery的每個選擇Ajax調用
單個項目的HTML如下:
<div class="item">
<p class="image"><a onmousedown="return SearchSpring.Catalog.intellisuggest(this, 'eJyzNCvJT8thcDRwNDG2NDTXNXR1MdI1sTR21bW0NDDQdXa1cDI2cTE0d3RxY2AwBENjAwZzMyOG9KLMFAC61g1R', 'd1f18f7e3b14f73ded97ff0a97db67a2eb19b128322804efbe2f46bd5fcd3c1f')" href="http://208.69.47.49/ProductSearch/ProductDetail.aspx?ID=KEL-AF24-SR"><img onerror="this.onerror=null;this.src='//d1qhbfo7yqnkif.cloudfront.net/ajax_search/img/missing-image-75x75.gif';" src="//208.69.47.49/Contents/Images/PART18_100PX.GIF"></a></p>
<p class="name"><a onmousedown="return SearchSpring.Catalog.intellisuggest(this, 'eJyzNCvJT8thcDRwNDG2NDTXNXR1MdI1sTR21bW0NDDQdXa1cDI2cTE0d3RxY2AwBENjAwZzMyOG9KLMFAC61g1R', 'd1f18f7e3b14f73ded97ff0a97db67a2eb19b128322804efbe2f46bd5fcd3c1f')" href="http://208.69.47.49/ProductSearch/ProductDetail.aspx?ID=KEL-AF24-SR">VM2327T23A00T</a></p>
<p class="price">$388.00</p>
<p id="part_number">VM2327T23A00T</p>
</div>
這裏是我的jQuery的是在。每個換行:
var parts = [];
var listPrices = [];
SearchSpring.jQuery('id').each(function() {
parts.push(SearchSpring.jQuery(this).attr('part_number'));
//listPrices.push(SearchSpring.jQuery(this).attr('list_price_baan'));
});
//skus = skus.join(',');
SearchSpring.jQuery.ajax({
type: "POST",
url: "RealTimePricing.aspx/GetCustomerPrice",
data: "{partNumber:' " + parts + "', listPrice: ' " + listPrices + "'}",
contentType: "application/json; charset=utf-8",
dataType: "json",
async: true,
cache: false,
success: function (data) {
for (var id in data) {
var prices = data[id]['prices'];
SearchSpring.jQuery('#' + id).text(prices);
}
}
});
有人能指出我這是爲什麼在每一行打破?我是否也正確地在ajax調用中正確調用「部件」?
問題是... – zerkms
'.attr('part_number')'?你的意思是'.attr('id')'是'part_number'嗎? – undefined
我不認爲你正確地在數據參數中包含數組。 'parts'是一個數組,而不是一個字符串。如果它在每一行都打破了,你應該有一個javascript錯誤。它是什麼? –