模糊comarison是你所需要的 - 有代碼here,將比較兩個字符串,並給你一個得分從0取決於他們有多接近。這將取決於你有多接近自動替代。
例子的結果:
server text fuzzy score
------- -------- -----------
hotmail hotmale 0.7619048
hotmail hot 0.4285714
hotmail notmail 0.8571429
hotmail NotEvenClose 0.1944444
hotmail hotmail 1
hotmail yellow 0.0952381
hotmail homtail 0.7142857
的源代碼已經GNU下發行次級GPL
鏈路腐爛的情況下,下面的代碼:
Public Function Fuzzy(ByVal s1 As String, ByVal s2 As String) As Single
Dim i As Integer, j As Integer, k As Integer, d1 As Integer, d2 As Integer, p As Integer
Dim c As String, a1 As String, a2 As String, f As Single, o As Single, w As Single
'
' ******* INPUT STRINGS CLEANSING *******
'
s1 = UCase(s1) 'input strings are converted to uppercase
d1 = Len(s1)
j = 1
For i = 1 To d1
c = Mid(s1, i, 1)
Select Case c
Case "0" To "9", "A" To "Z" 'filter the allowable characters
a1 = a1 & c 'a1 is what remains from s1 after filtering
j = j + 1
End Select
Next
If j = 1 Then Exit Function 'if s1 is empty after filtering
d1 = j - 1
s2 = UCase(s2)
d2 = Len(s2)
j = 1
For i = 1 To d2
c = Mid(s2, i, 1)
Select Case c
Case "0" To "9", "A" To "Z"
a2 = a2 & c
j = j + 1
End Select
Next
If j = 1 Then Exit Function
d2 = j - 1
k = d1
If d2 < d1 Then 'to prevent doubling the code below s1 must be made the shortest string,
'so we swap the variables
k = d2
d2 = d1
d1 = k
s1 = a2
s2 = a1
a1 = s1
a2 = s2
Else
s1 = a1
s2 = a2
End If
If k = 1 Then 'degenerate case, where the shortest string is just one character
If InStr(1, s2, s1, vbBinaryCompare) > 0 Then
Fuzzy = 1/d2
Else
Fuzzy = 0
End If
Else '******* MAIN LOGIC HERE *******
i = 1
f = 0
o = 0
Do 'count the identical characters in s1 and s2 ("frequency analysis")
p = InStr(1, s2, Mid(s1, i, 1), vbBinaryCompare)
'search the character at position i from s1 in s2
If p > 0 Then 'found a matching character, at position p in s2
f = f + 1 'increment the frequency counter
s2 = Left(s2, p - 1) & "~" & Mid(s2, p + 1)
'replace the found character with one outside the allowable list
'(I used tilde here), to prevent re-finding
Do 'check the order of characters
If i >= k Then Exit Do 'no more characters to search
If Mid(s2, p + 1, 1) = Mid(s1, i + 1, 1) Then
'test if the next character is the same in the two strings
f = f + 1 'increment the frequency counter
o = o + 1 'increment the order counter
i = i + 1
p = p + 1
Else
Exit Do
End If
Loop
End If
If i >= k Then Exit Do
i = i + 1
Loop
If o > 0 Then o = o + 1 'if we got at least one match, adjust the order counter
'because two characters are required to define "order"
finish:
w = 2 'Weight of characters order match against characters frequency match;
'feel free to experiment, to get best matching results with your data.
'If only frequency is important, you can get rid of the second Do...Loop
'to significantly accelerate the code.
'By altering a bit the code above and the equation below you may get rid
'of the frequency parameter, since the order counter increments only for
'identical characters which are in the same order.
'However, I usually keep both parameters, since they offer maximum flexibility
'with a variety of data, and both should be maintained for this project
Fuzzy = (w * o + f)/(w + 1)/d2
End If
End Function