我在使用json時遇到異常。我JSONPresr類是遵循org.json.JSONObject無法轉換爲JSONArray
import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStream;
import java.io.InputStreamReader;
import java.io.UnsupportedEncodingException;
import org.apache.http.HttpEntity;
import org.apache.http.HttpResponse;
import org.apache.http.client.ClientProtocolException;
import org.apache.http.client.methods.HttpPost;
import org.apache.http.impl.client.DefaultHttpClient;
import org.json.JSONException;
import org.json.JSONObject;
import android.os.AsyncTask;
import android.util.Log;
public class JSONParser {
static InputStream is = null;
static JSONObject jObj = null;
static String json = "";
// constructor
public JSONParser() {
}
public JSONObject getJSONFromUrl(String url) {
// Making HTTP request
try {
// defaultHttpClient
DefaultHttpClient httpClient = new DefaultHttpClient();
HttpPost httpPost = new HttpPost(url);
HttpResponse httpResponse = httpClient.execute(httpPost);
HttpEntity httpEntity = httpResponse.getEntity();
is = httpEntity.getContent();
} catch (UnsupportedEncodingException e) {
e.printStackTrace();
} catch (ClientProtocolException e) {
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
}
try {
BufferedReader reader = new BufferedReader(new InputStreamReader(
is, "UTF-8"), 8);
StringBuilder sb = new StringBuilder();
String line = null;
while ((line = reader.readLine()) != null) {
sb.append(line + "\n");
}
is.close();
json = sb.toString();
System.out.println(" value in json sting"+json);
} catch (Exception e) {
Log.e("Buffer Error", "Error converting result " + e.toString());
}
// try parse the string to a JSON object
try {
jObj = new JSONObject(json);
} catch (JSONException e) {
Log.e("JSON Parser", "Error parsing data " + e.toString());
Log.e("JSON Parser", "Error parsing data [" + e.getMessage()+"] "+json);
System.out.println(" error is here");
}
// return JSON String
return jObj;
}
}
我對這些代碼
String TAG_user_detail = "user_details";
String TAG_user_id = "user_id";
String TAG_user_name = "user_name";
String TAG_user_phone = "user_phone";
String TAG_ref_id = "ref_id";
JSONArray user_detail_jsonarray = null;
JSONParser jParser = new JSONParser();
// getting JSON string from URL
JSONObject json = jParser.getJSONFromUrl(url);
try {
// Getting Array of Contacts
user_detail_jsonarray = json.getJSONArray(TAG_user_detail);
// looping through All Contacts
for(int i = 0; i < user_detail_jsonarray.length(); i++){
JSONObject c = user_detail_jsonarray.getJSONObject(i);
// Storing each json item in variable
int id = c.getInt(TAG_user_id);
System.out.println("user id from json"+id);
String name_fromjson = c.getString(TAG_user_name);
System.out.println("user name from json"+name_fromjson);
int phone_no_fromjson = c.getInt(TAG_user_phone);
System.out.println("user phone from json"+phone_no_fromjson);
int ref_id_fromjson = c.getInt(TAG_ref_id);
System.out.println("user ref id from json"+ref_id_fromjson);
}
} catch (JSONException e) {
e.printStackTrace();
}
得到我的數據,但我countiniously在這一行越來越異常
user_detail_jsonarray = json.getJSONArray(TAG_user_detail);
我賭注追蹤消息是
{"ref_id":1295,"user_name":"chand","user_phone":"9620085675","user_id":"1"} at user_details of type org.json.JSONObject cannot be converted to JSONArray
我嘗試了很多鏈接,但不幸的是我無法獲得我的結果。請任何機構只是幫助我解決這個問題。在此先感謝所有
您正在爲'TAG_user_detail'獲取JSONObject而不是數組 –
請問您可以發佈一些代碼 – DJhon
哪些代碼?把你的完整的JSON。 –