2017-01-17 79 views
0

這段代碼有什麼問題?我的目標是在文本中找到網址,並將它們放入超鏈接標籤中。我正在使用舊的diegoperini正則表達式(學分https://mathiasbynens.be/demo/url-regex)。 如果我的輸入是一行,最後沒有空格,一切都會順利。c#中的多行和空格正則表達式問題

https://regex101.com/頁面顯示此正則表達式有效(全局和多重檢查),但c#找不到任何東西。

class Program 
    { 
     static void Main(string[] args) 
     { 
      String sourcestring = @"Tralala 

bla bla bla 

https://iqesonline.lt/index.cfm 
bla bla bla bla 
https://iqesonline.lt/index.cfm?id=99061c04-441e-a138-8254-6c441f7f59b5 

ulala. 

trampampam"; 
      // WORKS sourcestring = "https://iqesonline.lt/index.cfm?id=98061c04-441e-a138-8254-6c441f7f59b5"; 
      // DOES NOT WORK sourcestring = "https://iqesonline.lt/index.cfm?id=98061c04-441e-a138-8254-6c441f7f59b5 "; 
      ParseLinksToHtml(sourcestring); 


     } 
     public static string ParseLinksToHtml(string tekstas) 
     { 

      string result = tekstas; 
      if (!string.IsNullOrEmpty(result)) 
      { 
       // NOT WORKING Regex rx = new Regex(@"^(?:(?:https?|ftp)://)(?:\S+(?::\S*)[email protected])?(?:(?!10(?:\.\d{1,3}){3})(?!127(?:\.\d{1,3}){3})(?!169\.254(?:\.\d{1,3}){2})(?!192\.168(?:\.\d{1,3}){2})(?!172\.(?:1[6-9]|2\d|3[0-1])(?:\.\d{1,3}){2})(?:[1-9]\d?|1\d\d|2[01]\d|22[0-3])(?:\.(?:1?\d{1,2}|2[0-4]\d|25[0-5])){2}(?:\.(?:[1-9]\d?|1\d\d|2[0-4]\d|25[0-4]))|(?:(?:[a-z\u00a1-\uffff0-9]+-?)*[a-z\u00a1-\uffff0-9]+)(?:\.(?:[a-z\u00a1-\uffff0-9]+-?)*[a-z\u00a1-\uffff0-9]+)*(?:\.(?:[a-z\u00a1-\uffff]{2,})))(?::\d{2,5})?(?:/[^\s]*)?$"); 
       //NOT WORKING TOO 
       Regex rx = new Regex(@"^(?:(?:https?|ftp)://)(?:\S+(?::\S*)[email protected])?(?:(?!10(?:\.\d{1,3}){3})(?!127(?:\.\d{1,3}){3})(?!169\.254(?:\.\d{1,3}){2})(?!192\.168(?:\.\d{1,3}){2})(?!172\.(?:1[6-9]|2\d|3[0-1])(?:\.\d{1,3}){2})(?:[1-9]\d?|1\d\d|2[01]\d|22[0-3])(?:\.(?:1?\d{1,2}|2[0-4]\d|25[0-5])){2}(?:\.(?:[1-9]\d?|1\d\d|2[0-4]\d|25[0-4]))|(?:(?:[a-z\u00a1-\uffff0-9]+-?)*[a-z\u00a1-\uffff0-9]+)(?:\.(?:[a-z\u00a1-\uffff0-9]+-?)*[a-z\u00a1-\uffff0-9]+)*(?:\.(?:[a-z\u00a1-\uffff]{2,})))(?::\d{2,5})?(?:/[^\s]*)?$", RegexOptions.Multiline | RegexOptions.IgnoreCase); 
       result = rx.Replace(result, delegate (Match match) 
       { 
        string url = match.ToString(); 
        if (url.ToLower().StartsWith("www.")) 
        { 
         url = "http://" + url; 
        } 
        return string.Format("<a href=\"{0}\" target=\"_blank\">{1}</a>", url, match.ToString()); 
       }); 
      } 
      return result; 
     } 


    } 
+0

爲什麼不https://開頭[^ \ s] * |的ftp:// [^ \ s] * – jdweng

+1

嘗試刪除 「^」 在開始時與 「$」 在你的格局結束 – Magnetron

回答

0

已測試工作有以下簡單的正則表達式的字符串:

@"(?:\w+):\/\/(?:[\[email protected]][\w.:@]+)\/?[\w\.?=%&=\[email protected]/$,]*"

產地:

Tralala 

bla bla bla 

<a href="https://iqesonline.lt/index.cfm" target="_blank">https://iqesonline.lt/index.cfm</a> 
bla bla bla bla 
<a href="https://iqesonline.lt/index.cfm?id=99061c04-441e-a138-8254-6c441f7f59b5" target="_blank">https://iqesonline.lt/index.cfm?id=99061c04-441e-a138-8254-6c441f7f59b5</a> 

ulala. 

trampampam 
+0

這個正則表達式在「htttttttts:// .....」上失敗。它表明它是有效的url –

+0

誰說'htttttttts://'不是一個有效的協議? –

0

正確的答案是:刪除 「^」 和 「$」 使它工作。答案屬於磁控管。謝謝。

Regex rx = new Regex(@"^(?:(?:https?|ftp)://)(?:\S+(?::\S*)[email protected])?(?:(?!10(?:\.\d{1,3}){3})(?!127(?:\.\d{1,3}){3})(?!169\.254(?:\.\d{1,3}){2})(?!192\.168(?:\.\d{1,3}){2})(?!172\.(?:1[6-9]|2\d|3[0-1])(?:\.\d{1,3}){2})(?:[1-9]\d?|1\d\d|2[01]\d|22[0-3])(?:\.(?:1?\d{1,2}|2[0-4]\d|25[0-5])){2}(?:\.(?:[1-9]\d?|1\d\d|2[0-4]\d|25[0-4]))|(?:(?:[a-z\u00a1-\uffff0-9]+-?)*[a-z\u00a1-\uffff0-9]+)(?:\.(?:[a-z\u00a1-\uffff0-9]+-?)*[a-z\u00a1-\uffff0-9]+)*(?:\.(?:[a-z\u00a1-\uffff]{2,})))(?::\d{2,5})?(?:/[^\s]*)?$", RegexOptions.Multiline | RegexOptions.IgnoreCase);