NSubstitute模擬一個無效的方法與參數

Question

我是新來的NSubstitute，我試圖嘲笑void方法與2 out參數，我很確定我做錯了。

我有一個CustomerDataAccess類具有以下簽名的方法：

void GetCustomerWithAddresses(int customerId, 
           out List<Customer> customers, 
           out List<Address> addresses); 

的CustomerRepository調用它GetCustomer方法，然後調用CustomerDataAccess.GetCustomerWithAddresses DAL方法。 DAL方法然後輸出兩個out參數，一個用於客戶，另一個用於地址。存儲庫方法然後使用AutoMapper將兩個對象從DAL方法映射到存儲庫然後返回的業務域。

這是我到目前爲止的代碼，它不工作。我的研究並沒有幫助我確定我需要做些什麼來解決這個問題。我如何設置我的out參數的值？

// Arange 
ICustomerDataAccess customerDataAccess = Substitute.For<ICustomerDataAccess>(); 
IList<Customer> customers; 
IList<Address> addresses; 

customerDataAccess.When(x => x.GetCustomerWithAddresses(
    1, out customers, out addresses)) 
    .Do(x => 
    { 
     customers = new List<Customer>() { new Customer() { CustomerId = 1, CustomerName = "John Doe" } }; 
     addresses = new List<Address>() { new Address() { AddressId = 1, AddressLine1 = "123 Main St", City = "Atlanta" } }; 
    }); 

CustomerRepository sut = new CustomerRepository(customerDataAccess); 

// Act 
Customer customer = sut.GetCustomer(1); 

// Assert 
Assert.IsNotNull(customer); 

Answer 1

out參數是使用其參數位置作爲索引進行更新。這在Returnsdocumentation for NSubstitute中有解釋。所以，對於你的具體情況，你正在填充第二和第三個參數，所以你應該設置你的電話，像這樣：

customerDataAccess.When(x => x.GetCustomerWithAddresses(1, out customers, out addresses)) 
.Do(x => 
{ 
    x[1] = new List<Customer>() { new Customer() { CustomerId = 1, CustomerName = "John Doe" } }; 
    x[2] = new List<Address>() { new Address() { AddressId = 1, AddressLine1 = "123 Main St", City = "Atlanta" } }; 
});