串聯XML沒有類型轉換爲字符串

Question

我有我的SQL SERVER數據庫

<XMLData> 
... 
<Type>1</Type> 
... 
</XMLData> 

和

<XMLData> 
... 
<Type>2</Type> 
... 
</XMLData> 

和

<XMLData> 
... 
<Type>3</Type> 
... 
</XMLData> 

最終輸出各種表格生成以下XML我需要的是單人組合如下：

<AllMyData> 
    <XMLData> 
     ... 
     <Type>1</Type> 
     ... 
    </XMLData> 
    <XMLData> 
     ... 
     <Type>2</Type> 
     ... 
    </XMLData> 
    <XMLData> 
     ... 
     <Type>3</Type> 
     ... 
    </XMLData> 
<AllMyData> 

注 - 我組合的所有獨立元素都具有相同的標籤名稱。

在此先感謝您查看此信息。

Answer 1

我有我的SQL SERVER數據庫的各種表格生成以下XML

取決於你如何擁有它，但如果它在一個XML變量中，你可以這樣做。

declare @XML1 xml 
declare @XML2 xml 
declare @XML3 xml 

set @XML1 = '<XMLData><Type>1</Type></XMLData>' 
set @XML2 = '<XMLData><Type>2</Type></XMLData>' 
set @XML3 = '<XMLData><Type>3</Type></XMLData>' 

select @XML1, @XML2, @XML3 
for xml path('AllMyData') 

Answer 2

如果您使用for xml type，則可以合併XML列而不投射它們。例如：

select * 
from (
     select (
       select 1 as Type 
       for xml path(''), type 
       ) 
     union all 
     select (
       select 2 as Type 
       for xml path(''), type 
       ) 
     union all 
     select (
       select 3 as Type 
       for xml path(''), type 
       ) 
     ) as Data(XmlData) 
for xml path(''), root('AllMyData'), type 

此打印：

<AllMyData> 
    <XmlData> 
     <Type>1</Type> 
    </XmlData> 
    <XmlData> 
     <Type>2</Type> 
    </XmlData> 
    <XmlData> 
     <Type>3</Type> 
    </XmlData> 
</AllMyData> 

Answer 3

作爲附錄的Mikael埃裏克森的答案 - 如果你有，你需要不斷地添加節點，然後想組一個過程，一個節點下，這是做這件事：

declare @XML1 XML 
declare @XML2 XML 
declare @XML3 XML 
declare @XMLSummary XML 

set @XML1 = '<XMLData><Type>1</Type></XMLData>' 
set @XMLSummary = (SELECT @XMLSummary, @XML1 FOR XML PATH('')) 

set @XML2 = '<XMLData><Type>2</Type></XMLData>' 
set @XMLSummary = (SELECT @XMLSummary, @XML2 FOR XML PATH('')) 

set @XML3 = '<XMLData><Type>3</Type></XMLData>' 
set @XMLSummary = (SELECT @XMLSummary, @XML3 FOR XML PATH('')) 


SELECT @XMLSummary FOR XML PATH('AllMyData') 

Answer 4

我需要做同樣的事情，但不知道有多少行/變量有關，沒有額外的模式添加，所以這裏是我的解決方案。遵循這種模式，我可以根據需要生成儘可能多的代碼片段，將它們合併，在PROCS之間傳遞它們，甚至可以將它們從proc中返回，並在任何時候將它們包裝在容器中，而不用修改數據，也不必強制將XML結構添加到我的數據。我將這種方法與HTTP端點一起使用來提供XML Web服務，並使用另一種將XML轉換爲JSON的技巧來提供JSON WebServices。

-- SETUP A type (or use this design for a Table Variable) to temporarily store snippets into. The pattern can be repeated to pass/store snippets to build 
    -- larger elements and those can be further combined following the pattern. 
    CREATE TYPE [dbo].[XMLRes] AS TABLE(
     [xmlResult] [xml] NULL 
    ) 
    GO 


    -- Call the following as much as you like to build up all the elements you want included in the larger element 
    INSERT INTO @XMLRes (xmlResult) 
     SELECT 
      ( 
       SELECT 
        'foo' '@bar' 
       FOR XML 
        PATH('SomeTopLevelElement') 
      ) 

    -- This is the key to "concatenating" many snippets into a larger element. At the end of this, add " ,ROOT('DocumentRoot') " to wrapp them up in another element even 
    -- The outer select is a time from user2503764 that controls the output column name 

    SELECT (
    SELECT XmlData as [*] 
    FROM 
     (
     SELECT 
      xmlResult AS [*] 
     FROM 
      @XmlRes 
     WHERE 
      xmlResult IS NOT NULL 
     FOR XML PATH(''), TYPE 
     ) as DATA(XmlData) 
    FOR XML PATH('') 
    ) as [someColumnName] 

Answer 5

我不能評論，但可以回答，所以即使我認爲評論更合適，我會擴展什麼rainabba回答上面添加更多的控制。我的.Net代碼需要知道返回的列名，所以我不能依賴自動生成的名稱，但需要上面提供的提示rainabba。

通過這種方式，xml可以有效地連接成單行，並將結果列命名。您可以使用相同的方法將結果分配給XML變量，並從PROC返回。

SELECT (
SELECT XmlData as [*] 
FROM 
    (
    SELECT 
     xmlResult AS [*] 
    FROM 
     @XmlRes 
    WHERE 
     xmlResult IS NOT NULL 
    FOR XML PATH(''), TYPE 
    ) as DATA(XmlData) 
FOR XML PATH('') 
) as [someColumnName] 

Answer 6

ALTER PROCEDURE usp_fillHDDT @code詮釋

AS BEGIN

DECLARE @HD XML，@ DT XML;

SET NOCOUNT ON; 
select invhdcode, invInvoiceNO,invDate,invCusCode,InvAmount into #HD 
from dbo.trnInvoiceHD where invhdcode=@Code 

select invdtSlNo No,invdtitemcode ItemCode,invdtitemcode ItemName, 
invDtRate Rate,invDtQty Qty,invDtAmount Amount ,'Kg' Unit into #DT from 
dbo.trnInvoiceDt where invDtTrncode=@Code 

set @HD = (select * from #HD HD FOR XML AUTO,ELEMENTS XSINIL); 
set @DT = (select* from #DT DT FOR XML AUTO,ELEMENTS XSINIL); 

SELECT CAST ('<OUTPUT>'+ CAST (ISNULL(@HD,'') AS VARCHAR(MAX))+ CAST (ISNULL(@DT,'') AS VARCHAR(MAX))+ '</OUTPUT>' AS XML) 

END

Answer 7

public String ReplaceSpecialChar(String inStr) 
{ 
    inStr = inStr.Replace("&", "&"); 
    inStr = inStr.Replace("<", "&lt;"); 
    inStr = inStr.Replace(">", "&gt;"); 
    inStr = inStr.Replace("'", "&#39;"); 
    inStr = inStr.Replace("\"", "&quot;"); 
    return inStr; 
}