我從阿賈克斯獲得JSON數據,並認爲我接近完成這一操作,但由於某些原因,我的UL不填充,我無法找到任何調試信息,以幫助JSON數據。到UL
有人能指出我正確的方向嗎?
json data :
{"data":[{"racer_id":73,"racing_nbr":"4","entry_id":131},
{"racer_id":9,"racing_nbr":"48","entry_id":132},
{"racer_id":525,"racing_nbr":"7","entry_id":133},
{"racer_id":534,"racing_nbr":"11","entry_id":134},
{"racer_id":213,"racing_nbr":"72","entry_id":135},
{"racer_id":574,"racing_nbr":"66f","entry_id":136}]}
$('.list-group-item').click(function() {
var data = 'class_id='+ $(this).attr('rel') + '&event_id=' +<?php echo $_GET['event_id']; ?>
// POST to server using $.post or $.ajax
$.ajax({
data: data,
type: 'GET',
dataType: 'JSON',
url: 'php/builder/getRidersScoringHeats.php',
success: function(data) {
var obj = data, // get entry object (array) from JSON data
ul = $("#sortable"); // create a new ul element
// iterate over the array and build the list
for (var i = 0, l = obj.length; i < l; ++i) {
ul.append("<li class='ui-state-default' id='item-" + obj[i].entry_id + "'>" + obj[i].racing_nbr + " - " + obj[i].racer_id + "</li>");
}
$("#sortable").append(ul); // add the list to the DOM
}
});
});
任何幫助將不勝感激。
在此先感謝。
請進行的jsfiddle。 –