排序與絃樂地圖與校書郎

Question

我想用排序校書郎地圖口音，通過它顯然只能使用該名單與作品

林：

import java.text.* 

    Collator collator = Collator.getInstance() 
    collator.setStrength(Collator.PRIMARY) 
    def list = [ 
    [name:"áaa", title:"foo1"], 
    [name:"zzz", title:"foo2"], 
    [name:"éee", title:"foo3"], 
    [name:"ába", title:"foo4"], 
    [name:"aaa", title:"foo5"] 
] 

    Collections.sort(list.name, collator); 

    ​list.collect{it.name}​ 

它返回[áaa, zzz, éee, ába, aaa]

但它應該返回：[áaa, aaa,ába,éee, zzz]

我該如何解決它？我需要保留原始地圖。 也許我可以使用其他職業Collat​​or

謝謝！

Answer 1

Collections.sort修改列表list.name，您正在實時創建並且以前沒有存儲該列表。它確實得到排序，但結果丟失之後：

更新：添加排序而不丟失地圖結構。

import java.text.* 

def collator = Collator.instance 
collator.strength = Collator.PRIMARY 

def list = [ 
    [name:"áaa"], 
    [name:"zzz"], 
    [name:"éee"], 
    [name:"ába"], 
    [name:"aaa"] 
] 

listc = list*.name 

Collections.sort(listc, collator) 

assert listc == ['áaa', 'aaa', 'ába', 'éee', 'zzz'] 


// Sorting without losing the map structure. 

sortedList = list.sort(false) { a, b -> collator.compare a.name, b.name } 

assert sortedList == [ 
    [name:"áaa"], 
    [name:"aaa"], 
    [name:"ába"], 
    [name:"éee"], 
    [name:"zzz"], 
]