使用燒瓶MethodView

Question

我試圖適應這一點：

http://flask.pocoo.org/docs/views/

到藍圖本身（基於其他藍圖我看了）。從應用程序中抽象出api註冊到藍圖初始化中。這是來自燒瓶文檔的代碼，並做了一些更改。

這似乎工作：

class MyAPI(MethodView): 

    def __init__(self, name): 
     self.name = name 
     bp = Blueprint(name, __name__) 
     bp_endpoint = '{0}_api'.format(name) 
     bp_url = '/{0}/'.format(name) 
     bp_pk = '{0}_tag'.format(name) 
     self.register_api(bp, bp_endpoint, bp_url, bp_pk, 'string') 
     self._blueprint = bp 

    def register_api(self, blueprint, endpoint, url, pk='id', pk_type='int'): 
     view_func = self.as_view(endpoint) 
     blueprint.add_url_rule(url, defaults={pk: None}, 
         view_func=view_func, methods=['GET',]) 
     blueprint.add_url_rule(url, view_func=view_func, methods=['POST',]) 
     blueprint.add_url_rule('{0}<{1}:{2}>'.format(url, pk_type, pk), view_func=view_func, 
         methods=['GET', 'PUT', 'DELETE']) 

    def get(self, my_tag): 
     #... with post, put methods etc. 

然後在我的應用我就可以做到這一點：

m = MyAPI('my') 
app.register_blueprint(m._blueprint) 

這似乎是工作，註冊了網址，這樣我就可以得到：

Map([<Rule '/my/' (POST, OPTIONS) -> my.my_api>, 
<Rule '/my/<my_tag>' (PUT, HEAD, DELETE, OPTIONS, GET) -> my.my_api>, 
<Rule '/static/<filename>' (HEAD, OPTIONS, GET) -> static>, 
<Rule '/my/' (HEAD, OPTIONS, GET) -> my.my_api>]) 

但是，我現在去路線時遇到錯誤（我剛剛嘗試過GET）：

Traceback (most recent call last): 
    File "/media/686e26f8-c6d4-4448-8fe4-c19802726dcb/projects/1_current/private/pycleaver/venv/lib/python2.7/site-packages/flask/app.py", line 1518, in __call__ 
    return self.wsgi_app(environ, start_response) 
    File "/media/686e26f8-c6d4-4448-8fe4-c19802726dcb/projects/1_current/private/pycleaver/venv/lib/python2.7/site-packages/flask/app.py", line 1506, in wsgi_app 
    response = self.make_response(self.handle_exception(e)) 
    File "/media/686e26f8-c6d4-4448-8fe4-c19802726dcb/projects/1_current/private/pycleaver/venv/lib/python2.7/site-packages/flask/app.py", line 1504, in wsgi_app 
    response = self.full_dispatch_request() 
    File "/media/686e26f8-c6d4-4448-8fe4-c19802726dcb/projects/1_current/private/pycleaver/venv/lib/python2.7/site-packages/flask/app.py", line 1264, in full_dispatch_request 
    rv = self.handle_user_exception(e) 
    File "/media/686e26f8-c6d4-4448-8fe4-c19802726dcb/projects/1_current/private/pycleaver/venv/lib/python2.7/site-packages/flask/app.py", line 1262, in full_dispatch_request 
    rv = self.dispatch_request() 
    File "/media/686e26f8-c6d4-4448-8fe4-c19802726dcb/projects/1_current/private/pycleaver/venv/lib/python2.7/site-packages/flask/app.py", line 1248, in dispatch_request 
    return self.view_functions[rule.endpoint](**req.view_args) 
    File "/media/686e26f8-c6d4-4448-8fe4-c19802726dcb/projects/1_current/private/pycleaver/venv/lib/python2.7/site-packages/flask/views.py", line 83, in view 
    self = view.view_class(*class_args, **class_kwargs) 
**TypeError: __init__() takes exactly 2 arguments (1 given)** 

aaand這是比我能想到的atm低一個或兩個水平。任何輸入讚賞我所錯過的。我認爲它最初可能與register_api中的view_func有關。

編輯：

排序的答案

類MyAPI（MethodView）：

def __init__(self, name): 
    self.name = name 
    bp = Blueprint(name, __name__) 
    self.endpoint = '{0}_api'.format(name) 
    self.url = '/{0}/'.format(name) 
    self.pk = '{0}_tag'.format(name) 
    self._blueprint = bp 
    self.register_api(self._blueprint, self.endpoint, self.url, self.pk) 

def register_api(self, bp, endpoint, url, pk ='id', pk_type='int'): 
    view_func = self.__class__.as_view(endpoint) 
    bp.add_url_rule(url, defaults={pk: None}, 
        view_func=view_func, methods=['GET',]) 
    bp.add_url_rule(url, view_func=view_func, methods=['POST',]) 
    bp.add_url_rule('{0}<{1}:{2}>'.format(url, pk_type, pk), view_func=view_func, 
        methods=['GET', 'PUT', 'DELETE']) 

Answer 1

我想你能保持你的初始化方法只有一個參數：

def __init__(self): 
    bp = Blueprint("what?", __name__) # here 
    bp_endpoint = '{0}_api'.format(name) 
    bp_url = '/{0}/'.format(name) 
    bp_pk = '{0}_tag'.format(name) 
    self.register_api(bp, bp_endpoint, bp_url, bp_pk, 'string') 
    self._blueprint = bp 

或在as_view中給出足夠的值而不修改您的初始化方法。

def register_api(self, blueprint, endpoint, url, pk='id', pk_type='int'): 
    view_func = self.as_view(endpoint, name="what?") # here 
    # ... omit ... 

但在我看來，在方法視圖內創建藍圖並不是一個好主意。藍圖是一個子應用程序，應由許多觀點共享。