的Python：catch異常和重複碼

Question

我有這樣的代碼：

import imaplib, re 
import os 
import time 

conn = imaplib.IMAP4_SSL("imap.gmail.com", 993) 
conn.login("ddd", "dddd") 

while(True): 
     unreadCount = re.search("UNSEEN (\d+)", conn.status("INBOX", "(UNSEEN)")[1][0]).group(1) 
     print unreadCount 

     if int(unreadCount) > 10: 
       print "restarting..." 

     time.sleep(50) 

，有時會失去連接和停止工作。我怎樣才能捕獲異常並在每次破解時啓動代碼？

感謝

Answer 1

import imaplib, re 
import os 
import time 

while True: 
    try: 
     conn = imaplib.IMAP4_SSL("imap.gmail.com", 993) 
     conn.login("ddd", "dddd") 

     while True : 
       unreadCount = re.search("UNSEEN (\d+)", conn.status("INBOX", "(UNSEEN)")[1][0]).group(1) 
       print unreadCount 

       if int(unreadCount) > 10: 
         print "restarting..." 

       time.sleep(50) 
    except HypotheticalException: 
     pass 

Answer 2

使用try ...除了

try: 
    unreadCount = re.search("UNSEEN (\d+)", conn.status("INBOX", "(UNSEEN)")[1][0]).group(1) 
    if int(unreadCount) > 10: 
      print "restarting..." 

    time.sleep(50) 
except Exception: 
    pass 

Answer 3

試試這個：

import imaplib, re 
import os 
import time 


for n in range(3): 
try: 
    conn = imaplib.IMAP4_SSL("imap.gmail.com", 993) 
    conn.login("ddd", "dddd") 
    while(True): 
     unreadCount = re.search("UNSEEN (\d+)", conn.status("INBOX", "(UNSEEN)")[1][0]).group(1) 
     print unreadCount 

     if int(unreadCount) > 10: 
      print "restarting..." 

     time.sleep(50) 
    break 
except Exception, e: 
    if n == 2: 
     print >>sys.stderr, "Failure During processing, restarting..." 
     print >>sys.stderr, e 

您可以將N設置要允許但多次嘗試。

編輯： 嗯，經過進一步細讀，似乎我得到你的代碼有點錯了。我編輯並修復了我的版本。你將需要調整和編輯你的while循環，因爲我不完全確定你要做什麼。

編輯2： 既然您需要重新連接並再試一次，我已經移動了try塊中的conn節。