如何在SQL中編寫計算查詢？

Question

使用SQL Server 2000

我的查詢。

SELECT 
    (Format(IIf(CLng(OutTime) > 180000, CDate('18:00:00'), CDate(Format(OutTime, '00:00:00'))) - IIf(CLng(InTime) < 90000, CDate('09:00:00'), CDate(Format(InTime, '00:00:00'))), 'hh:nn:ss')) As WorkTime, 
    (Format(IIf(CLng(InTime) < 90000, CDate('09:00:00') - CDate(Format(InTime, '00:00:00')), 0) + IIf(CLng(OutTime) > 180000, CDate(Format(OutTime, '00:00:00')) - CDate('18:00:00'), 0), 'hh:nn:ss')) As OverTime 
FROM table 

以上查詢是Access查詢，我想要寫在SQL中相同的查詢。

條件。

我想計算在180000之前090000（HH：MM：SS）進入工作時間之前的時間，在180000之後的 090000進入加班時間。

銀泰，Outime數據類型爲varchar在數據庫

是新的SQL Server 2000

如何寫從上述相同的SQL查詢？

Answer 1

這裏是直譯查詢TSQL 2000 雖然，它可以改寫爲更好的性能：

Select Convert(char(8), 
      case when DateAdd(Day,-DateDiff(Day, 0, OutTime), OutTime)>'18:00:00' 
       Then Cast('18:00:00' as datetime) 
       Else DateAdd(Day,-DateDiff(Day, 0, OutTime), OutTime) 
      End 
      - 
      Case when DateAdd(Day,-DateDiff(Day, 0, InTime), InTime) <'09:00:00' 
       Then Cast('09:00:00' as datetime) 
       Else DateAdd(Day,-DateDiff(Day, 0, InTime), InTime) 
      End, 
      8 
     ) as WorkTime, 
    Convert(char(8), 
      Case when DateAdd(Day,-DateDiff(Day, 0, InTime), InTime) <'09:00:00' 
       Then Cast('09:00:00' as datetime) - 
        DateAdd(Day,-DateDiff(Day, 0, InTime), InTime) 
       Else Cast('00:00:00' as datetime) 
      End 
      + 
      case when DateAdd(Day,-DateDiff(Day, 0, OutTime), OutTime)>'18:00:00' 
       Then DateAdd(Day,-DateDiff(Day, 0, OutTime), OutTime) - 
        Cast('18:00:00' as datetime) 
       Else Cast('00:00:00' as datetime) 
      End, 
      8 
     ) as OverTime 
From Table 

後來補充：

如果銀泰和OutTime有一部分時間（日期部分是1900年1月1日），您可以直接使用InTime和OutTime。否則，您必須提取一部分時間從datetime列，如：

DateAdd(Day,-DateDiff(Day, 0, OutTime), OutTime) 

（這是隻得到部分時間以最快的方式）

相反的：

DateAdd(Day,-DateDiff(Day, 0, OutTime), OutTime)>'18:00:00' 

您可以使用

Datepart(hh,OutTime)>17 

PS因爲你的時間存儲爲字符串yoiu不需要只獲取時間部分。你可以將它們轉換成日期時間，或者你也可以寫

cast(left(inTime,2) as int) < 9 

Answer 2

作爲初學者，請瀏覽本網站，其中介紹如何將Access SQL語句轉換爲SQL服務器使用的T-SQL。

http://weblogs.sqlteam.com/jeffs/archive/2007/03/30/Quick-Access-JET-SQL-to-T-SQL-Cheatsheet.aspx

Answer 3

我不認爲有一個非常容易和簡單的方式來做到這一點 - 最明顯的是因爲在VARCHAR存儲時間值 - 這是真正使這個棘手.....

無論如何，我使用了兩種功能 - 一種dbo.GetSeconds，它將時間值（'103500' - > 10:35:00小時）的字符串表示轉換爲秒數，然後是第二種功能dbo.GetOvertime，檢測是否存在是任何加班。

CREATE FUNCTION dbo.GetSeconds(@input varchar(20)) 
RETURNS int 
AS BEGIN 
    DECLARE @Hour INT 
    DECLARE @Minute INT 
    DECLARE @Second INT 

    DECLARE @TotalSeconds INT 

    SET @Hour = CAST(SUBSTRING(@input, 0, LEN(@input)-3) AS INT) 
    SET @Minute = CAST(LEFT(RIGHT(@input, 4), 2) AS INT) 
    SET @Second = CAST(RIGHT(@input, 2) AS INT) 

    SET @TotalSeconds = @Hour * 3600 + @Minute * 60 + @Second 

    RETURN @TotalSeconds 
END 


CREATE FUNCTION dbo.GetOvertime(@fromSeconds INT, @toSeconds INT) 
RETURNS int 
AS BEGIN 
    DECLARE @Overtime INT 

    SET @Overtime = 0 

    IF @fromSeconds < 32400 -- 32400 seconds = 09:00 hours 
    SET @Overtime = @OverTime + (32400 - @fromSeconds) 

    IF @toSeconds > 64800 -- 64800 seconds = 18:00 hours 
    SET @Overtime = @OverTime + (@toSeconds - 64800) 

    RETURN @Overtime 
END 

有了這兩個功能，我可以很容易計算出你在找什麼：

SELECT 
    dbo.GetOvertime(dbo.GetSeconds(InTime), dbo.GetSeconds(OutTime)) 'Overtime', 
    (dbo.GetSeconds(OutTime) - dbo.GetSeconds(InTime) - 
    dbo.GetOvertime(dbo.GetSeconds(InTime), dbo.GetSeconds(OutTime))) 'Worktime', 
FROM YourTable 

這是涉及到一點 - 正如我所說，如果你是在SQL Server上2008年和使用TIME數據類型，事情會變得更容易！

馬克

Answer 4

你可以使用子和DATEADD轉換的「090000」一個真正的日期時間字段。然後你可以使用CASE和DATEDIFF來拆分工作和加班。最終格式化可以使用CONVERT完成。這裏有一個例子：

select 
    case when outtime-intime > '9:00:00' then '09:00:00' 
    else convert(varchar(30), outtime-intime, 108) 
    end as WorkTime, 
    case when outtime-intime <= '9:00:00' then '00:00:00' 
    else convert(varchar(30), outtime-intime-'9:00:00', 108) 
    end as OverTime 
from (
    select 
    dateadd(hh,cast(substring('090000',1,2) as int),0) + 
    dateadd(mi,cast(substring('090000',3,2) as int),0) + 
    dateadd(ss,cast(substring('090000',5,2) as int),0) as InTime, 
    dateadd(hh,cast(substring('180500',1,2) as int),0) + 
    dateadd(mi,cast(substring('180500',3,2) as int),0) + 
    dateadd(ss,cast(substring('180500',5,2) as int),0) as OutTime 
) vw 

這將打印：

09:00:00 00:05:00 

Answer 5

這裏是SQL Server 2000的代碼2005+能做到這一點，而無需使用交叉連接的子查詢。

Select DateAdd(mi, (Case When bef<0 Then bef else 0 end + Case When aft<0 Then aft else 0 end), diff) as WorkTome, 
     DateAdd(mi, (Case When bef>0 Then bef else 0 end + Case When aft>0 Then aft else 0 end), 0) as OverTime 
From (  
Select outTime-inTime as diff, 
     DateDiff(mi,t.inTime,'09:00') as bef, 
     DateDiff(mi,'18:00',t.outTime) as aft 
    From Table t) as a 

如果你銀泰和outTime列HASE日期部分也查詢略有不同：

Select DateAdd(mi, (Case When bef<0 Then bef else 0 end + Case When aft<0 Then aft else 0 end), diff) as WorkTome, 
     DateAdd(mi, (Case When bef>0 Then bef else 0 end + Case When aft>0 Then aft else 0 end), 0) as OverTime 
From (  
Select outTime-inTime as diff, 
     DateDiff(mi, DateAdd(Day,-DateDiff(Day, 0, t.inTime), t.inTime),'09:00') as bef, 
     DateDiff(mi,'18:00',DateAdd(Day,-DateDiff(Day, 0, t.OutTime), t.OutTime)) as aft 
    From #t t) as a 

Answer 6

我錯過了銀泰和outTime的類型。 這裏是varchar的版本

錯過了，但你只需要做Cast（inTime as datetime）。 使用前面2個查詢中的第一個：

Select DateAdd(mi, (Case When bef<0 Then bef else 0 end + Case When aft<0 Then aft else 0 end), diff) as WorkTome, 
     DateAdd(mi, (Case When bef>0 Then bef else 0 end + Case When aft>0 Then aft else 0 end), 0) as OverTime 
    From (  
    Select Cast(t.outTime as datetime)-Cast(t.inTime as datetime) as diff, 
     DateDiff(mi,Cast(t.outTime as datetime),'09:00') as bef, 
     DateDiff(mi,'18:00',Cast(t.outTime as datetime)) as aft 
    From Table t) as a